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2 years ago

What is the source of fuel that is most widely used today?

1 answer:

34kurt2 years ago

8 0

The source of fuel that is most widely used today is Natural gas. The answer is letter C. The rest of the choices do not answer the question above,

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PLZ Help i need to turn it in before Friday

nikklg [1K]

Answer:

What type of work do u have? LOL

Explanation:

8 0

2 years ago

Draw the major organic product(s) of the reaction of p-bromoaniline with HNO2, HCl.

NARA [144]

Answer:

The major product from this reaction is 4-bromobenzene diazonium chloride.

Explanation:

The reaction of p-bromoaniline with HNO2 and HCl produces diazonium salt. When primary aromatic amines are nitrosated with nitrous acid in the presence of a strong acid such as HCl, diazonium salts are frequently formed. The diazonium salts are a crucial step in the production of halides and azo compounds. The necessary reaction mechanism is depicted in the illustration in the diagram below.

3 0

2 years ago

A 50.0 mL graduated cylinder has a mass of 65.1 g. When it is filled with an unknown liquid to the 49.3 mL mark, the cylinder an

Delvig [45]

Answer: The density of liquid is $1.12g/cm^3$

Explanation:

We are given:

Mass of cylinder, $m_1$ = 65.1 g

Mass of liquid and cylinder combined, M = 120.5 g

Mass of liquid, $m_2$ = $(M-m_1)=(120.5-65.1)g=55.4g$

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Mass of liquid = 55.4 g

Volume of liquid = 49.3 mL = $49.3 cm^3$ (Conversion factor: $1mL=1cm^3$ )

Putting values in above equation, we get:

$\text{Density of liquid}=\frac{55.4g}{49.3cm^3}\\\\\text{Density of liquid}=1.12g/cm^3$

Hence, the density of liquid is $1.12g/cm^3$

3 0

3 years ago

Which of these does not cause a change in the reaction rate?

VMariaS [17]

A. density
Reaction rate increases with concentration.

8 0

2 years ago

Read 2 more answers

A 50.0g g sample of 16n decays to 12.5g in 14.4 seconds. What is its half life

mixas84 [53]

T is amount after time t
Ao is initial amount 
t is time 
HL is half life 

log (At) = log [ Ao x (1/2)^(t/HL) ] 
log (At) = log Ao + log (1/2)^(t/HL) 
log (At) = log Ao + (t/HL) x log (1/2) 

( log At - log Ao) / log (1/2) = t / HL 
log (At/Ao) / log (1/2) = t / HL 

HL = t / [( log (At / Ao)) / log (1/2) ] 

HL = 14.4 s / [ ( log (12.5 / 50) / log (1/2) ] 

HL = 14.4 s / 2 = 7.2 seconds

8 0

3 years ago