Answer:
The spring constant of the spring is 205.42 N/m.
Explanation:
Springs have their own natural "spring constants" that define how stiff they are. The letter k is used for the spring constant, and it has the units N/m.
k = -F/x
The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.
Given:
mass of object in SHM = m = 0.30 kg
Time period of the spring mass system = 0.24s
Spring constant = k ?
Finding 'k' using Time period 'T':
We know that 
Answer:
E₄ = - 0.85 eV
E₂ = - 3.4 eV
Ephoton = 2.55 eV
Explanation:
The sum of Kinetic Energy (K) and Potential Energy (U) of the Helium atom is equal to the total energy of Helium atom in the specified state N. From Bohr's atomic model, the energy of a hydrogen atom in state N is given as:
En = K + U = (-1/n²)(13.6 eV)
a)
Here,
n = 4
Therefore,
E₄ = (-1/4²)(13.6 eV)
<u>E₄ = - 0.85 eV</u>
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b)
Here,
n = 2
Therefore,
E₂ = (-1/2²)(13.6 eV)
<u>E₂ = - 3.4 eV</u>
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c)
The energy of photon emitted in the transition from level 4 to level 2 will be equal to the difference in the energy of both levels:
Ephoton = ΔE = E₄ - E₂
Ephoton = - 0.85 eV - (- 3.4 eV)
<u>Ephoton = 2.55 eV</u>
<u></u>
Newtons third law of motion applies to football as when the ball is thrown, force is applied to the football thrown forward and also force back to the player. Therefore it states that every action has a reaction. The player does not get a huge force back from throwing the football due to the player having a bigger mass than the football being thrown.
In short, when the football is throw, there is a reaction with the ball and the player accordingly with the force put into the ball.
Answer:
We conclude that the total distance traveled by the object in the 4 seconds is 36 m.
Explanation:
Given
- Initial velocity u = 5.0 m/s
- Acceleration a = 2.0 m/s²
To determine
The total distance traveled by the object in the 4.0 seconds is
<u>Important Tip:</u>
We can determine the total distance traveled by the object in the 4.0 seconds by using the equation of motion such as
where
- s = distance
- u = initial velocity
- a = acceleration
- t = time
substituting u = 5.0, a = 2, and t = 4 in the formula
m
Therefore, we conclude that the total distance traveled by the object in the 4 seconds is 36 m.
Answer:
Drop by a factor of 64
Explanation:
By Newtons law of gravity,
where;
G = Universal gravitaional constant
r = distance between center of gravities of two objects
m₁,m₂ = masses of thee objects.
F = Gravitational force.
m = 
(mass = volume into density.
So when radius is halved, mass drops by a factor of 8,
m' = 
= 
So in substitution to the equation,
