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Aloiza [94]
4 years ago
13

The speed of light is 3.0 x 108 m/s. How far does light travel in 2.4 minutes? Identify all variables, write a formula, show all

work, Label your answer.
Physics
1 answer:
Leviafan [203]4 years ago
6 0

Answer: 4,32 10^10 m

Explanation: The relationshiop between the light speed, distance and time is given by:

speed of light = distance/time

distance= speed of ligth * time

distance= 3*10^8 m/s * 2.4*60 s= 4,32*10^10 m

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During a laboratory experiment, the temperature of the gas in a balloon is varied and the
lys-0071 [83]
A. The IV is the temperature of gas in the balloon.

B. The DV is the volume of the balloon.

This is because the temperature of the gas is the variable being manipulated in the experiment (Independent) and the volume is changing based on the shifts of the temperature (thus volume is Dependent).
4 0
3 years ago
A uniform rod is 2. 0 m long and has mass 15 kg. What is most nearly the rod's mass moment of inertia?
trapecia [35]

The rod's mass moment of inertia is 5kgm².

<h3>Moment of Inertia:</h3>

The "sum of the product of mass" of each particle with the "square of its distance from the axis of rotation" is the formula for the moment of inertia.

The Parallel axis Theorem can be used to compute the moment of inertia about the end of the rod directly or to derive it from the center of mass expression. I = kg m². We can use the equation for I of a cylinder around its end if the thickness is not insignificant.

If we look at the rod we can assume that it is uniform. Therefore the linear density will remain constant and we have;

or = M / L = dm / dl

dm = (M / L) dl

I =  \int\limits^M_0 {r^2} \, dm

I = \int\limits^\frac{L}{2} _\frac{-L}{2}  {I^2 (M/L)} \, dl

Here the variable of the integration is the length (dl). The limits have changed from M to the required fraction of L.

I = \int\limits^\frac{L}{2} _\frac{-L}{2}  {I^2 (M/L)} \, dl

I = \frac{M}3L}[(\frac{L^3}{2^3}   - \frac{-L^3}{2^3} )]\\\\I = \frac{1}{12}ML^2

Mass of the rod = 15 kg

Length of the rod = 2.0 m

Moment of Inertia, I = \frac{1}{12}15 (2)^2

                               = 5 kgm²

Therefore, the moment of inertia is 5kgm².

Learn more about moment of inertia here:

brainly.com/question/14119750

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4 0
2 years ago
according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sled
astra-53 [7]

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

<h3>Newton's third law</h3>

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

<h3>Application of the newton's third law</h3>

Force with which the sledgehammer hits the wall = 1000 N

  • From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.

Thus, the force exerted by the sledgehammer on the wall = -1000 N

  • The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Learn more about Newton's third law and force at: brainly.com/question/13874955

7 0
3 years ago
What type of reproduction does slime mold have?<br> (I need the answer right now)<br> thanks:)
notka56 [123]

The slime mold will create a stalk with new spores in it, called a "fruiting body". These spores will make new patches of slime mold. This is a form of asexual reproduction.

<h2>Mark as brainliest?</h2>
8 0
4 years ago
Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles
Anna007 [38]

Question

Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles  travelled in a straight line and some were deflected at different angles.

Which statement best describes what Rutherford concluded from the motion of the particles?

A) Some particles travelled through empty spaces between atoms and some particles were deflected by electrons.

B) Some particles travelled through empty parts of the atom and some particles were deflected by electrons.

C) Some particles travelled through empty spaces between atoms and some particles were deflected by small areas of high-density positive charge in atoms.

D) Some particles travelled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.    

Answer:

 

The right answer is C)    

Explanation:

In the experiment described above, a piece of gold foil was hit with alpha particles, which have a positive charge. Alpha particles <em>α</em> were used because, if the nucleus was positive, then it would deflect the positive particles. The principles of physics posit that electric charges of the same orientation repel.  

So most as expected some of the alpha particles went right through meaning that the gold atoms comprised mostly empty space except the areas that were with a dense population of positive charges. This area became known as the "nucleus".  

Due to the presence of the positive charges in the nucleus, some particles had their paths bent at large angles others were deflected backwards.

Cheers!

6 0
3 years ago
Read 2 more answers
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