X component of force Fx=Fcos45=50×cos×45
Y component of force Fy=Fsin45=50×sin×45
Answer:
Acceleration of the car is
.
Explanation:
It is given that,
Initial speed of the car, u = 29 m/s
Finally it reaches a speed of, v = 34 m/s
Distance, d = 110 m
We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :




So, the acceleration of the car as it speeds up is
. Hence, this is the required solution.
K.E=1/2mv^2 K.E=1/2multiply1multiply8^2=32joules
The standard unit is KW/hr, = 1,000W/hr.
(85 + 60) = 145W.
You need to find its fraction of 1,000W., so (145/1000) = 0.145 KWH.
(0.145 x 10p) = 1.45p. per hr.