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3 years ago

Does salt or fresh water make a difference in floating of ships? plz answer ASAP will give brainliest to the best answer

Physics

2 answers:

ch4aika [34]3 years ago

5 0

Answer:

The density of salt water is more than that of density of fresh water, so so salt and fresh water makes a difference in floating of ships.

qaws [65]3 years ago

3 0

Answer:

Yes, salt or fresh water makes a difference in floating of ships.

Explanation:

Salt water is heavier than freshwater, the ships float higher in salt water than fresh water.

The density is higher, so less salt water will be displaced, and the ship will float higher.

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1. Describe what conversation of momentum means.

Snowcat [4.5K]

Answer:

1. The conversation of momentum is when a person or object has momentum and transfers it to another person or object.

Explanation:

2. Like if someone is on a swing and kicks someone in front of him. He stops and the kid in front of him falls over because the momentum was transferred.

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3 years ago

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Two objects attract each other with a gravitational force of magnitude 1.02 10-8 N when separated by 19.7 cm. If the total mass

Yakvenalex [24]

Answer:

mass 1 = 1.60kg

mass 2 = 3.54kg

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3 years ago

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According to the evolutionary perspective of mate selection, why do men and women exhibit different preferences in mate selectio

Alla [95]

C. Each gender has differing attraction cues and priorities.

<h3>Why do men and women exhibit different preferences in mate selection?</h3>

Men and women exhibit different preferences in mate selection because both have different attraction cues and priorities for their partner. These cues and priorities leads to difference in preference of life partner.

So we can conclude that Each gender has differing attraction cues and priorities.

Learn more about mate here: brainly.com/question/25261401

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6 0

2 years ago

Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces

Mandarinka [93]

Answer: $0.81\times 10^{16}$ beta particles

Explanation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass = 14.0 g

Molar mass = 137 g/mol

$\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles$

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

1 mole of cesium contains atoms = $6.023\times 10^{23}$

0.102 moles of cesium contains atoms = $\frac{6.023\times 10^{23}}{1}\times 0.102=0.614\times 10^{23}$

The relation of atoms with time for radioactivbe decay is:

$N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}$

Where $N_t$ =atoms left undecayed

$N_0$ = initial atoms

t = time taken for decay = 3 minutes

${t_{\frac{1}{2}}}$ = half life = 30.0 years = $1.577\times 10^7$ minutes

The fraction that decays : $1-(\frac{1}{2})^{\frac{3}{1.577\times 10^7}}=1.32\times 10^{-7}$

Amount of particles that decay is = $0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}$

Thus $0.81\times 10^{16}$ beta particles are emitted by a 14.0-g sample of cesium-137 in three minutes.

7 0

3 years ago

Ignoring air resistance and the little friction from the plastic tube, the magnet was a freely-falling object in each trial. If

horsena [70]

Answer:

emf will also be 10 times less as compared to when it has fallen $40 \mathrm{m}$

Explanation:

We know, from faraday's law-

$e m f=-N \frac{\Delta \Phi}{\Delta T}$

and $\Phi=B . A$

So, as the height increases the velocity with which it will cross the ring will also increase. $(v=\sqrt{2 g h})$

Given

$\mathrm{V} 1(\text { Speed at } 40 \mathrm{m})=2 \mathrm{x} \mathrm{V} 2(\text { speed at } 10 \mathrm{m})$

$\sqrt{2 g h_{2}}=2 \times \sqrt{2 g h_{1}}=28.28 \mathrm{m} / \mathrm{s}$

Now, from $40 \mathrm{cm}$

$V_{3}=\sqrt{2 g h_{3}}=\sqrt{2 \times 10 \times 0.4}=2.82 \mathrm{m} / \mathrm{s}$

From equation a and b we see that velocity when dropped from $40 \mathrm{m}$ is 10 times greater when height is 40 $\mathrm{cm}$ so, emf will also be 10 times less as compared to when it has fallen $40 \mathrm{m}$

4 0

3 years ago