<h3><u>Answer;</u></h3>
Dipole-dipole and hydrogen bonding
<h3><u>Explanation;</u></h3>
- <em><u>A solution of water and ethanol contains the dipole-dipole forces and hydrogen bonds as the intermolecular forces between molecules.</u></em>
- <em><u>Hydrogen bonding is a type of interactions between molecules that occurs when a partially negative atom such as oxygen end of one of the molecules is attracted to a partially positive hydrogen end of another molecule.</u></em>
- <em><u>Dipole-dipole forces</u></em> results from the unsymmetrical distribution of electrons, thus the polarity does not balance, thus resulting to a dipole attraction between molecules.
Answer:
The answer to your question is SO₂ + 3H₂ ⇒ H₂S + 2H₂O
Explanation:
Reaction
SO₂ + H₂ ⇒ H₂S + H₂O
Reactants Elements Products
1 Sulfur 1
2 Hydrogen 4
2 Oxygen 1
This reaction is unbalanced so we need to balance it.
SO₂ + 3H₂ ⇒ H₂S + 2H₂O
Reactants Elements Products
1 Sulfur 1
6 Hydrogen 6
2 Oxygen 2
Now, the reaction is balanced
Answer:
1. water will freeze at a temperature below 32 degrees fahrenheit 0 degree celsius.
2. Ice will melt at a temperature above 32 degrees fahrenheit 0 degrees celsius.
3. water boils at 212 degrees fahrenheit or 100 degrees celsius.
Times it bye for then ur answer will be 80
Answer is: molality od sodium chloride is 2,55 mol/kg.
V(solution) = 100 ml.
m(solution) = d(solution) · V(solution).
m(solution) = 1,10 g/ml · 100 ml.
m(solution) = 110 g.
ω(NaCl) = 13,0% = 0,13.
m(NaCl) = ω(NaCl) · m(solution).
m(NaCl) = 0,13 · 110 g.
m(NaCl) = 14,3 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 14,3 g ÷ 58,5 g/mol.
n(NaCl) = 0,244 mol.
m(H₂O) = 110 g - 14,3 g.
m(H₂O) = 95,7 g = 0,0957 kg.
b(NaCl) = n(NaCl) ÷ m(H₂O).
b(NaCl) = 0,244 mol ÷ 0,0957 kg.
b(NaCl) = 2,55 mol/kg.
