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diamong [38]
1 year ago
8

How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f

ertilizers. A) Write an exponential decay function for a 50mg sample. b) Find the amount of P - 32 remaining after 84 days.
Chemistry
1 answer:
BaLLatris [955]1 year ago
4 0

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

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6 0
3 years ago
Help me please !! How to solve it ??
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Reactant side-
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The first one is balanced for you 
There is 1 calcium on each side 2 oxygens on each side and 2 hydrogens on each side


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