2) D = m/V. Knowns: V = (4 x 4 x 4) = (64) D = 2.7
2.7 = m/(64)
172.8 = m or with significant figures, 170
3) Knowing the model of the atom is crucial becuase without understanding what everything is made up of, then there is no way of telling how it is going to react with outside things. Knowing the model of the atom can better help us visualize what it looks like and it can also tell us how it is going to react baced on its propertys and what it is made of.
4) Dalton's theory tells us that 1, all matter is made of atoms, which are indivisible and indestructiable. This does not agree with todays findings because we know that atoms can be broken up into sub atomic particals, and even those sub atomic particals can be broken down even further to sub-sub-atomic particals such as quarks and borons. 2, We also know about Isotopes. Isotopes are the same atom but with different atomic weights becaus of the amount of nutrons in the nuclei.
5) If an element has 12 protons and 17 neutron, in order to be stable and found in nature, the atom must have 12 protons because protons are positive and neutrons have a charge of 0 so in order to balence the atom out, the electrons, with a negitive charge, must be the same number as the protons.
Heating up, mostly. Solid can be heated to liquid, then to gas, then eventually to plasma.
An acid is a compound which will give H+ ions or H3O^+ ions
the reaction will be
![[Mn(H_{2}O )_{6} ^{+3} +H_{2}O --> [MnOH(H_{2}O)_{5}]^{+2} + H_{3}O^{+}](https://tex.z-dn.net/?f=%5BMn%28H_%7B2%7DO%20%29_%7B6%7D%20%5E%7B%2B3%7D%20%2BH_%7B2%7DO%20--%3E%20%5BMnOH%28H_%7B2%7DO%29_%7B5%7D%5D%5E%7B%2B2%7D%20%2B%20H_%7B3%7DO%5E%7B%2B%7D)
Thus as there is evolution of H_{3}O^{+} the Mn+3 is an acid
A heterogeneous mixture because you can still tell apart the components in the mixture. You can differentiate between the milk and the cereal.
Answer:
1132.8 ml of water
Explanation:
you have an aqueous solution contains 158.2 g KOH per liter
so concentration =158.2/56 = 2.825M
Molarity =2.825
that means you have 2.825 moles of KOH in 1.00L solution
Mass of Soluet(KOH)= 152.8g
Volume of solution= 1.00L
density of solution= 1.13g/cm3 =1.13g/ml
therefore mass of solution = VolumeX density = 1000mL X 1.13g/ml.=1130g
Mass of solvent(water)= mass of solution- mass of solute(KOH)=1130-152.8= 997.2g
Molality= moles of solute/mass of solvent(Kg)
=2.825/(997.2/1000)= 2.832molal
to prepare a 0.250 molal solution of KOH, starting with 100.0ml ofthe orginal solution
0.250*X =2.832 *100
X = 1132.8 ml of water you have to add