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ozzi
3 years ago
13

What is the magnitude of force required to accelerate a car of mass 1.7 * 10 ^ 3 kg by 4.75 m/s

Physics
1 answer:
Gnesinka [82]3 years ago
8 0

What is the magnitude of force required to accelerate a car of mass 1.7 × 10³ kg by 4.75 m/s²

Answer:

F = 8.075 N

Explanation:

Formula for force is;

F = ma

Where;

m is mass

a is acceleration

F = 1.7 × 10³ × 4.75

F = 8.075 N

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A particle of charge 2.0 x 10^-8C experiences an upward force of magnitude 4.0 x10^-6 when it is placed in a particular point in
koban [17]

Answer:

a) The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) The electric force is 2.0\times 10^{-6} newtons.

Explanation:

a) Let suppose that electric field is uniform, then the following electric field can be applied:

E = \frac{F_{e}}{q} (1)

Where:

E - Electric field, measured in newtons per coulomb.

F_{e} - Electric force, measured in newtons.

q - Electric charge, measured in coulombs.

If we know that F_{e} = 4.0\times 10^{-6}\,N and q = 2.0\times 10^{-8}\,C, then the electric field at that point is:

E = \frac{4.0\times 10^{-6}\,N}{2.0\times 10^{-8}\,C}

E = 2.0\times 10^{2}\,\frac{N}{C}

The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) If we know that E = 2.0\times 10^{2}\,\frac{N}{C} and q = 1.0\times 10^{-8}\,C, then the electric force is:

F_{e} = E\cdot q

F_{e} = \left(2.0\times 10^{2}\,\frac{N}{C} \right)\cdot (1.0\times 10^{-8}\,C)

F_{e} = 2.0\times 10^{-6}\,N

The electric force is 2.0\times 10^{-6} newtons.

7 0
3 years ago
An ideal gas Carnot cycle with air in a piston cylinder has a high temperature of 1000 K and a heat rejection at 400 K. During t
vivado [14]

Answer:

W / n = - 9133 J / mol, W / n = 3653 J / mol , e = 0.600

Explanation:

The Carnot cycle is described by

      e= 1 - Q_{c} / Q_{H} = 1 - T_{c} / T_{H}

     

In this case they indicate that the final volume is

         V = 3V₀

In the part of the heat absorption cycle from the source is an isothermal expansion

         W = n RT ln (V₀ / V)

         W / n = 8.314 1000 ln (1/3)

          W / n = - 9133 J / mol

During the part of the isothermal compression in contact with the cold focus, as in a machine the relation of volumes is maintained in this part is compressed three times

            W / n = 8.314 400 (3)

           W / n = 3653 J / mol

The efficiency of the cycle is

            e = 1- 400/1000

            e = 0.600

6 0
3 years ago
A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car?
aksik [14]

ANSWER


C. F=4.5 \times10^3. newtons


EXPLANATION


According to Newton's second law,



F_{net}=ma, where



m=1.00\times 10^3kg is the mass measured in kilograms.


and


a=4.5ms^{2} is the acceleration in metres per second square.



We substitute these values to obtain,


F=1.00\times10^3 \times 4.5.



We rearrange to get,


F=1.00\times4.5 \times10^3.


We multiply out the first two numbers and leave our answer in standard form to get,



F=4.5 \times10^3 N.



The correct answer is C


3 0
3 years ago
Two pool balls, each moving at 2 m/s, roll toward each other and collide. Suppose after bouncing apart, each moves at 2 m/s. Thi
stira [4]

Answer:D

Explanation:according to the law of conservation of energy/momentum, when two bodies collides, their total momentum and energy before and after collision are equal. Given that the two bodies move with the same velocities after collision, means that the law has not been violated since momentum = mass x velocity (where mass is constant)

4 0
3 years ago
Uveďte príklady nesúhlasnej alebo nejednoznačnej komunikácie?
umka2103 [35]

Answer:hiuwiauwney jejjksuu

Explanation:

5 0
2 years ago
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