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ozzi
3 years ago
13

What is the magnitude of force required to accelerate a car of mass 1.7 * 10 ^ 3 kg by 4.75 m/s

Physics
1 answer:
Gnesinka [82]3 years ago
8 0

What is the magnitude of force required to accelerate a car of mass 1.7 × 10³ kg by 4.75 m/s²

Answer:

F = 8.075 N

Explanation:

Formula for force is;

F = ma

Where;

m is mass

a is acceleration

F = 1.7 × 10³ × 4.75

F = 8.075 N

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Team A created a larger net force opposite in direction to the lesser net force of Team B.

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A string is wrapped around a uniform disk of mass M = 1.2 kg and radius R = 0.07 m. (Recall that the moment of inertia of a unif
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Explanation:

Given that,

Mass of disk = 1.2 kg

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Radius of rod = 0.11 m

Mass of small disk = 0.5 kg

Force = 29 N

Time t = 0.022 s

\theta=0.023\ m

Distance d= 0.039 m

(I). We need to calculate the speed of the apparatus

Using work energy theorem

W=\Delta K.E

Fd=\dfrac{1}{2}mv^2

v=\sqrt{\dfrac{2Fd}{M+4m}}

Where, m = total mass

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F = force

d = distance

Put the value into the formula

v=\sqrt{\dfrac{2\times29\times0.039}{1.2+4\times0.5}}

v=0.840\ m/s

(b). We need to calculate the angular speed of the apparatus

Using formula of torque

\tau=I\alpha

F\times=(\dfrac{1}{2}MR^2+4mb^2)\alpha

29\times0.07=(\dfrac{1}{2}\times1.2\times0.07^2+4\times0.5\times0.11^2)\alpha

\alpha=\dfrac{29\times0.07}{0.02714}

\alpha=74.79\ rad/s^2

We need to calculate the angular speed of the apparatus

Using equation of angular motion

\omega=\omega_{0}+\alpha t

Put the value into the formula

\omega=0+74.79\times0.022

\omega=1.645\ rad/s

(c).  We need to calculate the angular speed of the apparatus

Using equation of angular motion

\omega_{0}^2=\omega^2+2\alpha t

Put the value into the formula

\omega_{0}^2=1.645^2+2\times74.79\times0.022

\omega=2.44\ rad/s

Hence, This is required equation.

7 0
3 years ago
Gordon throws a baseball into the air. It rises, stops when it reaches its greatest height, and then falls back down to the grou
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Answer:

A) When the baseball is rising

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When an object like the baseball is thrown into the air, the kinetic energy  is gradually converted into potential energy. When the baseball rises to its maximum height, the kinetic energy becomes zero and the kinetic energy is fully converted into potential energy.

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3 years ago
A train is traveling at 28 m/s. It slows to 6 m/s in 4 s. Calculate the distance the train
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At a point 1.2 m out from the hinge, 14.0 N force is exerted at an angle of 27 degrees to the moment arm in a plane which is per
geniusboy [140]

Answer:

\tau = 7.63 Nm

Explanation:

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now we have

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now from above formula we have

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here we know that

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\tau = 7.63 Nm

3 0
3 years ago
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