What do crystal of table salt look like?

In grassland regions, rainy seasons and drought seasons determine, in part, the _____. kinds of resident organisms spread of fir

qaws [65]

kinds of resident organisms

6 0

3 years ago

Read 2 more answers

A star is known to be moving at 8.46km/s toward the earth. If you observe the spectral line to be at 5.02nm, at what wavelength

anastassius [24]

Answer:

$\lambda_x=5.019858nm$

Explanation:

From the question we are told that

Speed of star $S=8.46km/s$

Distance of spectral line $\lambda_0= 5.02nm$

Generally the equation for wavelength with respect to spectral lines is mathematically given by

$\lambda=\lambda _0 *\frac{v}{c}$

where

$\lambda_0= length\ of\ spectral\ line$

$c=The\ speed\ of\ light$

$v= speed\ of\ moving\ object$

therefore

$\lambda=5.02*10^{-9} *\frac{8.46*10^{12}}{299 792 458*10^9}$

$\lambda=1.42*10^{-4} nm$

Generally the equation for new wavelength is mathematically given as

$\lambda_x=\lambda _0-\lambda$

$\lambda_x=5.02 nm-1.42*10^{-4} nm$

$\lambda_x=5.02-1.42*10^{-4}$

Therefore

$\lambda_x=5.019858nm$

5 0

3 years ago

Which of the following is an example of the concepts of growth and development functioning together?

DedPeter [7]

Hello there.

Which of the following is an example of the concepts of growth and development functioning together? 

 C. Children learning to print their names

7 0

3 years ago

How does the search for exoplanets help us describe how science requires creativity?

Aliun [14]

Answer:

As the planets are very small and dark in comparison with stars, it makes them very hard to be found from earth.

Explanation:

Astronomy, of course, has a solution for this. As astronomers can't observe planets directly, they decided to observe the stars and search for the effects that planets have on them.

There are many ways of observing the exoplanets: Radial Velocity, Transit Photometry, Microlensing, Astrometry, Direct Imaging, etc.

Before all of this, scientist had to find ways to prove their theories. Most of their time they have spent in giving the creative answers.

Science and creativity are very much connected when we speak about the development of science. Rationality and creativity always go together.

In order to create an idea that other people will consider useful, it is important to use creativity. As no one has the exact answer when it comes to science, the adventure is to research the unknown.

5 0

3 years ago

Three ideal polarizing filters are stacked, with the polarizing axis of the second and third filters at 21 degrees and 61 degree

kvv77 [185]

Answer:

1

When second polarizer is removed the intensity after it passes through the stack is

$I_f_3 = 27.57 W/cm^2$

2 When third polarizer is removed the intensity after it passes through the stack is

$I_f_2 = 102.24 W/cm^2$

Explanation:

From the question we are told that

The angle of the second polarizing to the first is $\theta_2 = 21^o$

The angle of the third polarizing to the first is $\theta_3 = 61^o$

The unpolarized light after it pass through the polarizing stack $I_u = 60 W/cm^2$

Let the initial intensity of the beam of light before polarization be $I_p$

Generally when the unpolarized light passes through the first polarizing filter the intensity of light that emerges is mathematically evaluated as

$I_1 = \frac{I_p}{2}$

Now according to Malus’ law the intensity of light that would emerge from the second polarizing filter is mathematically represented as

$I_2 = I_1 cos^2 \theta_1$

$= \frac{I_p}{2} cos ^2 \theta_1$

The intensity of light that will emerge from the third filter is mathematically represented as

$I_3 = I_2 cos^2(\theta_2 - \theta_1 )$

$I_3= \frac{I_p}{2}(cos^2 \theta_1)[cos^2(\theta_2 - \theta_1)]$

making $I_p$ the subject of the formula

$I_p = \frac{2L_3}{(cos^2 \theta [cos^2 (\theta_2 - \theta_1)])}$

Note that $I_u = I_3$ as $I_3$ is the last emerging intensity of light after it has pass through the polarizing stack

Substituting values

$I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (61-21)])}$

$I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (40)])}$

$=234.622W/cm^2$

When the second is removed the third polarizer becomes the second and final polarizer so the intensity of light would be mathematically evaluated as

$I_f_3 = \frac{I_p}{2} cos ^2 \theta_2$

$I_f_3$ is the intensity of the light emerging from the stack

substituting values

$I_f_3 = \frac{234.622}{2} * cos^2(61)$

$I_f_3 = 27.57 W/cm^2$

When the third polarizer is removed the second polarizer becomes the

the final polarizer and the intensity of light emerging from the stack would be

$I_f_2 = \frac{I_p}{2} cos ^2 \theta_1$

$I_f_2$ is the intensity of the light emerging from the stack

Substituting values

$I_f_2 = \frac{234.622}{2} cos^2 (21)$

$I_f_2 = 102.24 W/cm^2$

7 0

3 years ago