Answer:
A
Explanation:
Straight line with a negative slope
On a velocity_time graph
The area of the Earth (Ae) that is irradiated by is given by:
Ae = 4πRe^2, where Re = Distance from Sun to Earth
Substituting;
Ae = 4π*(1.5*10^8*1000)^2 = 2.827*10^23 m^2
On the Earth, insolation (We) = Psun/Ae
Therefore,
Psun (Rate at which sun emits energy) = We*Ae = 1.4*2.827*10^23 = 3.958*10^23 kW = 3.958*10^26 W
Yes potential increases while kinetic decreases
Answer:
2856.96 J
0
0

6.78822 m/s
Explanation:
= Initial velocity = 9.6 m/s
g = Acceleration due to gravity = 9.81 m/s²
h = Height
The athlete only interacts with the gravitational potential energy. Air resistance is neglected.
At height y = 0
Kinetic energy

At height y = 0 the potential energy is 0 as

At maximum height her velocity becomes 0 so the kinetic energy becomes zero.
As the the potential and kinetic energy are conserved
The general equation

Half of maximum height



The velocity of the athlete at half the maximum height is 6.78822 m/s
Answer:
the answer is C i didnt mean to put b lol
Explanation: