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Darya [45]
3 years ago
13

a student standing between two walls shouts once.he hears the first echo after 3 seconds and the next after 5 seconds. calculate

the distance between the walls.​
Physics
1 answer:
Karolina [17]3 years ago
6 0

Explanation:

It took t_1 =1.5\:\text{s} for the sound to reach the 1st wall and at the same time time, the same sound took t_2 = 2.5\:\text{s} to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let x_1 be the distance of the person to the 1st wall and x_2 be the distance to the 2nd wall. So the distance between the walls X is

X = x_1 + x_2 = v_st_1 + v_st_2 = v_s(t_1 + t_2)

\:\:\:\:\:= (343\:\text{m/s})(4.0\:\text{s}) = 1372\:\text{m}

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5 0
3 years ago
Read 2 more answers
A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy. The energy used to do work
nika2105 [10]

Answer:

480J

Explanation:

Using the formula:

Delta U = Q - W

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W:Work (J)

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6 0
3 years ago
Can someone please help? Thank u!
Snowcat [4.5K]

Answer:

B. 7.5 m/s^2

Explanation:

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a= v-v/t

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7 0
3 years ago
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Artyom0805 [142]

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6 0
2 years ago
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6 0
3 years ago
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