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3 years ago

How to solve quadratic equations with the coefficient not equal to 1?

1 answer:

5 0

Which coefficient? There are multiple, as the general formula of a quadratic equation is $ax^2+bx+c$ .
There are a few ways, and if you can factorise by inspection that works, however the most effective way of solving equations that aren't obvious is to plug it into the quadratic formula:

$\boxed{x=-b +- \frac{ \sqrt{b^2-4ac} }{2a} }$

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(True or false)car traveling 20 meters per hour east of the mountain pass is example of velocity

stiv31 [10]

I believe the answer is True

6 0

3 years ago

Read 2 more answers

Using the quadratic formula, what is the value of x for x^2-4+5=0

PSYCHO15rus [73]

value of x is: x= i and x= -i

Step-by-step explanation:

We need to find the value of x from $x^2-4+5=0$ using quadratic formula.

The term is: $x^2+1=0$

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\$

Where a = 1, b=0,c=1

Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{0\pm\sqrt{(0)^2-4(1)(1)}}{2(1)}\\x=\frac{\pm\sqrt{-4}}{2}\\x=\frac{\pm2i}{2}\\x=\pm i$

So, value of x is: x= i and x= -i

Keywords: Quadratic formula

Learn more about quadratic formula at:

#learnwithBrainly

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4 years ago

You have $36,948.61 in a brokerage account, and you plan to deposit an additional $3,000 at the end of every future year until y

Luba_88 [7]

Current amount in account
P=36948.61

Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n

Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11

We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000

We can solve this by trial and error.

The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.

So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.

So it takes 15.00 years to reach the goal of 280000 years.

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3 years ago

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vazorg [7]

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3 0

3 years ago

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A baseball team played 147 regular season games. The ratio of the number of games they won to the number of games they lost was

makvit [3.9K]

Answer:

They won 63 and lost 84.

Step-by-step explanation:

147 in 7 parts

1 part= 21

ratio of 3 parts to 4 parts

3 parts=63

4 parts=84

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4 years ago