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3 years ago

What was the code phrase the japanese used to initiate the attack on pearl harbor

Engineering

2 answers:

UkoKoshka [18]3 years ago

8 0

Answer:

Tora!

Explanation:

It was an expression that illustrated the complete surprise of the attack.

yan [13]3 years ago

6 0

Answer:Itaka

Explanation:

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Please help describe the impact that a toy robot has had or could have on its intended audience

GuDViN [60]

Depending on the age the toy is made for it could teach younger children things such as letters and numbers and for a older kid it could teach them how different things are put in the robot to help it work

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3 years ago

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Technician A says you should place the air ratchet setting to

Bas_tet [7]

I think it’s b sry if I’m wrong tho

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3 years ago

Coulomb's Law Two point charges experience an attractive force of 10.8 N when they are separated by 2.4 m. VWhat force in newton

SashulF [63]

Answer:

The force between the charges when the separation decreases to 0.7 meters equals 126.955 Newtons

Explanation:

We know that for two point charges of magnitude $q_{1},q_{2}$ the magnitude of force between them is given by

$F=\frac{k_{e}q_{1}\cdot q_{2}}{r^{2}}$

where

$k_{e}$ is constant

$r$ is the separation between the charges

Initially when the charges are separated by 2.4 meters the force can be calculated as

$F_{1}=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\10.8=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\\therefore k_{e}\cdot q_{1}q_{2}=10.8\times 2.4^{2}=62.208$

Now when the separation is reduced to 0.7 meters the force is similarly calculated as

$F_{2}=\frac{k_{e}\cdot q_{1}q_{2}}{0.7^{2}}$

Applying value of the constant we get

$F_{1}=\frac{62.208}{0.7^{2}}$

Thus $F_{2}=126.955Newtons$

5 0

3 years ago

An inductor is energized as in the circuit of Fig. 2-4a. The circuit has L 10 mH and VCC 14 V. (a) Determine the required on tim

Savatey [412]

Answer:

A) 11.1 ms

B) 5.62 Ω

Explanation:

L ( inductance ) = 10 mH

Vcc = 14V

A) determine the required on time of the switch such that the peak energy stored in the inductor is 1.2J

first calculate for the current ( i ) using the equation for energy stored in an inductor hence

i = $\sqrt{\frac{2W}{L} }$ ----- ( 1 )

where : W = 1.2j , L = 10 mH

Input values into equation 1

i = 15.49 A

Now determine the time required with expression below

i( t ) = 15.49 A

L = 10 mH, Vcc = 14

hence the time required ( T-on ) = 11.1 ms

attached below is detailed solution

B) select the value of R such that switching cycle can be repeated every 20 ms

using the expression below

τ = $\frac{L}{R}$ ---- ( 2 )

but first we will determine the value of τ

τ = t-off / 5 time constants

= (20 - 11.1 ) / 5 = 1.78 ms

Back to equation 2

R = L / τ

= (10 * 10^-3) / (1.78 * 10^-3)

= 5.62 Ω

3 0

3 years ago

Your department's laser printer recently began printing a vertical black line near the edge of every printed page. What should y

WINSTONCH [101]

Answer:

Replace the toner cartridge

Explanation:

solution

when laser printer print black color liner vertical line print it is very frustrating that condition nearly empty toner cartridge

but first we clean the corona wire for that color line

and Reinstall the toner cartridges after Shake the toner cartridge side to side

if problem not solve than Clean the drum unit

and finally if not solve change the toner cartridge

so as that our problem will be resolve

5 0

3 years ago