Answer:
б₁ = 1.98 ksi
б₂ = 1.98 ksi
Explanation:
Calculating the component of stress acting at point A using circumferential stress equation, we have;
б₁ = p*r/t
= 90*11/0.25
= 3960 psi = 3.96 ksi
Calculating the component of stress acting at point A using longitudinal stress equation, we have;
б₂ = p*r/2*t
= 90*11 /2*0.25
= 1.98 ksi
Find attached of the volume element at point A.
Answer:
Z= 0.868
Explanation:
Given that
P= 3 MPa
T = 160 K
We know that
P v= Z R T
P= Pressure
v = specific volume
R= gas constant
T = Absolute temperature
Z= Compressibility factor
Here specific volume of gas is not given so we assume that specific volume gas
We know that for oxygen gas constant
R = 0.259 KJ/kg.K
Now by putting the values
P v = Z R T
3000 x 0.012 = Z x 0.259 x 160
Z= 0.868
So Compressibility factor is 0.868.
Answer: 2.93 ft/sec
Explanation: Calculate the volume/sec entering from the two inlets (Pipes 1 and 2), add them, and then calculate the flow in Pipe 3.
The table illustrates the approach. I calculated the volume of each pipe for a 1 foot section with the indicated diameters, divided by 2 for the radius of each using V = πr²h. Units of V are in^3/foot length. Now we can multiply that volume by the flow rate, in ft/sec, to obtain the flow rate in in^3/sec.
Add the two rates from Pipes 1 and 2 (62.14 in^3/sec) to arrive at the flow rate for Pipe 3 necessary to keep the water level constant. Calculate the volume of 1 foot of Pipe 3 (21.21 in^3/foot) and then divide this into the inflow sum of 62.14 in^3/sec to find the flow rate of Pipe 3 (in feet/sec) necessary to keep the water level constant.
That is 2.93 ft/sec.
