<span>(7x^4+x+14)/(x+2)
</span>(7x^4+x+14)----------------------|(x+2)
-14x³+x+14-------------------------7x³-14x²+28x-55------> q(x)
28x²+x+14
-55x+14
110+14=124------------------------> r(x)
<span>
</span>r(x)=124
b(x)=x+2
q(x)=7x³-14x²+28x-55

then
q(x) + r(x)/b(x)---------> (7x³-14x²+28x-55)+(124)/(x+2)

the answer is (7x³-14x²+28x-55)+(124)/(x+2)

4 0

3 years ago

What is the equation in slope-intercept form of a line that is perpendicular to y=2x+2 and passes through the point (4, 3)?

Ostrovityanka [42]

<h2>Answer: y = - ¹/₂ x + 5 </h2>

<h3>Step-by-step explanation: </h3>

<u>Find the slope of the perpendicular line</u>

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are negative-reciprocals of each other.

⇒ if the slope of this line = 2 (y = 2x + 2)

then the slope of the perpendicular line (m) = - ¹/₂

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

⇒ y - 3 = - ¹/₂ (x - 4)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

since y - 3 = - ¹/₂ (x - 4)

y = - ¹/₂ x + 5 (in slope-intercept form)

8 0

2 years ago