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zepelin [54]
3 years ago
7

The Prandtl number, Npr, is a dimensionless group important in heat transfer calculations. It defined as Cuk, where C, is the he

at capacity of a fluid, u is the fluid viscosity, and k is the thermal conductivity. For a particular fluid, C, = 0.583 J/(g.°C), k = 0.286 W/(m:°C), and 1936 lb./(ft·h). Estimate the value of Npr without using a calculator (remember, it is dimension less), showing your calculations; then determine it with a calculator.
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

The Prandlt number for this fluid is 1630.

Explanation:

The Prandlt number is defined as:

Pr=\frac{C_p\mu}{k}

To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.

\mu=1936\frac{lb}{ft*h}*\frac{1000g}{2.205lb}*\frac{3.281ft}{1m}*\frac{1h}{3600s}  \\ \\\mu=800 \frac{g}{m*s}

Now that we have coherent units, we can calculate Pr

Pr=\frac{C_p\mu}{k}=\frac{0.583*800}{0.286}= 1630

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Recall that you're hypothesis is that these values are the fractions of atoms that are still radioactive after n half life cycle
Sergeu [11.5K]

A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

<h3>What is a hypothesis?</h3>

A research hypothesis is a statement of expectation or prediction that will be tested by research. Before formulating your research hypothesis, read about the topic of interest to you.

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula,

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

Learn more about the hypothesis here:

brainly.com/question/17173491

#SPJ1

4 0
2 years ago
Calculate the enthalpy change for the reaction of hydrogen and chlorine using the bond energies below.
babunello [35]

Answer:

final-intial temperature= enthalpy change

8 0
3 years ago
If a position time graph has a constant slope, what can you infer about the<br> acceleration?
gogolik [260]

Answer:

Acceleration is zero.

Explanation:

The slope of a position time graph gives the velocity of the body.

If the slope is constant means the velocity is constant.

Now, acceleration is the measure of the change in velocity of a body over a given time interval.

So, the acceleration of a body is directly proportional to the change in velocity of the body.

If there is no change in velocity, this means that the acceleration of the body is zero.

Here, the slope is a constant implying that the velocity is a constant. So, there is no change in velocity. This implies that the acceleration is zero for the body in the given time interval.

Thus, if a position time graph has a constant slope, one can infer that the  acceleration is zero.

5 0
3 years ago
Mary starts from her house, walks 80 meters south, and stops to chat with her aunt on the sidewalk. After chatting for a few min
Olenka [21]
(80+125+45) / 10 = 250/10 =25
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the direction and stopping time is irrelevant to the problem.
6 0
4 years ago
Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO
zavuch27 [327]

Answer:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Explanation:

Hello,

In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons  4NOBr ( g )

The suitable equilibrium constant turns out:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Or in terms of the initial equilibrium constant:

K_2=K_1^2

Since the second reaction is a doubled version of the first one.

Best regards.

5 0
3 years ago
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