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cestrela7 [59]
3 years ago
7

Common properties of sodium , calcium , iron ,and gold

Chemistry
1 answer:
Fittoniya [83]3 years ago
7 0
Sodium, calcium, iron and gold are all metals. They all form metallic bonds, in the form of a shared electron cloud. They all have the electrical conductivity and metallic luster which comes with metallic bonds.
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g The following equation is given for the dissociation of the complex ion Ag(NH3) 2. The dissociation constant, Kd, is the equil
Sveta_85 [38]

Answer:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

Explanation:

Let's consider the dissociation reaction of the complex ion Ag(NH₃)₂⁺.

Ag(NH₃)₂⁺(aq) ⇄ Ag⁺(aq) + 2 NH₃(aq)

The dissociation constant, Kd, is the equilibrium constant for the dissociation of the complex ion, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

The dissociation constant for this reaction is:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

8 0
2 years ago
How many people were considered undernourished in Latin America and the Caribbean in 2018?
DochEvi [55]
D . 42.5 million…………
8 0
2 years ago
Help please science (7th grade)
hoa [83]

Answer:

17

Explanation:

Don't mind the random letters

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8 0
2 years ago
Read 2 more answers
What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv
statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

7 0
3 years ago
Question 2 (0 points)
bazaltina [42]

Answer:

The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

Explanation:

Given that,

Total color in spinner = 4

Let the area of four parts is equal in the spinner.

We need to calculate the probability of spinning red

Using formula of probability

P(A) = \dfrac{Number\ of\ red\ color\ outcome}{Total\ number\ of\ colors\ in\ the\ spinner}

Put the value into the formula

P(A)=\dfrac{1}{4}

We need to calculate the probability of odd number of the die

Using formula of probability

P(B) = \dfrac{Number\ of\ odd\ digits\ outcome}{Total\ number\ of\ digits\ in\ the\ die}

Put the value into the formula

P(B)=\dfrac{3}{6}

P(B)=\dfrac{1}{2}

We need to calculate the probability  of spinning red with the spinner or rolling an odd number with the  die

Using formula of probability of two events which is independent

P(A\ and\ B)=P(A)\times P(B)

Put the value into the formula

P(A\ and\ B)=\dfrac{1}{4}\times\dfrac{1}{2}

P(A\ and\ B)=\dfrac{1}{8}

Hence, The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

5 0
3 years ago
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