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denpristay [2]
3 years ago
11

Two students are working together to build two models. Both models will represent the molecular structure of sodium bicarbonate,

NaHCO3 commonly known as baking soda. The students are using toothpicks to represent bonds and jelly beans to represent atoms. Red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms, and blue jelly beans represent sodium atoms, white jellybeans represent hydrogen atoms, like jellybeans our cruise and carbon atoms, and we jellybeans that is an oxygen atoms.
Identify the number of each jelly bean needed to make both models.
Chemistry
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

<em>Note: Since no specific color was stated for oxygen atoms, the answer assigns blue colored jellybeans to represent oxygen atoms.J</em>

Explanation:

Sodium bicarbonate, NaHCO₃ is a compound composed of one atom of sodium, one atom of hydrogen, one atom of carbon and three atoms of oxygen.

Since red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms and blue jellybeans represent oxygen atoms, each of the two students will require the following number of each jellybean for their model of sodium carbonate: One red jellybean, one white jellybean, one black jellybean and three blue jellybeans.

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

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how do the properties of sodium chloride compare with the properties of its component elements, sodium
Orlov [11]

Sodium chloride is a nonreactive solid at room temperature, and is commonly known as table salt. The two elements that make up sodium chloride are sodium and chlorine. Sodium is a very reactive metal that tastes bad. Pure sodium is explosive when it comes in contact with water. Hope this helps

3 0
4 years ago
A sample of gas occupies 10.0 L at 240°C under a pressure of
NISA [10]

Answer: 1090°C

Explanation: According to combined gas laws

(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1 = initial pressure of gas = 80.0 kPa

V1 = initial volume of gas = 10.0 L

T1 = initial temperature of gas = 240 °C = (240 + 273) K = 513 K

P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

T2 = final temperature of gas

Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

T2 = 513 K × (1.3375) × (2)

T2 = 1372.275 K

T2 = (1372.275 - 273) °C

T2 = 1099 °C

8 0
3 years ago
Read 2 more answers
What is the molarity of formaldehyde in a solution containing 0.25 grams of formaldehyde per mL?
Vikentia [17]

Answer:

8.33mol/L

Explanation:

First, let us calculate the molar mass of of formaldehyde (CH2O). This is illustrated below:

Molar Mass of CH2O = 12 + (2x1) + 16 = 12 + 2 + 16 = 30g/mol

Mass of CH2O from the question = 0.25g

Number of mole CH2O =?

Number of mole = Mass /Molar Mass

Number of mole of CH2O = 0.25/30 = 8.33x10^-3mole

Now we can calculate the molarity of formaldehyde (CH2O) as follow:

Number of mole of CH2O = 8.33x10^-3mole

Volume = 1mL

Converting 1mL to L, we have:

1000mL = 1L

Therefore 1mL = 1/1000 = 1x10^-3L

Molarity =?

Molarity = mole /Volume

Molarity = 8.33x10^-3mole/1x10^-3L

Molarity = 8.33mol/L

Therefore, the molarity of formaldehyde (CH2O) is 8.33mol/L

3 0
3 years ago
IUPAC NAME FOR<br><br> [Fe(H2O)6](NO3)3
sdas [7]

Explanation:

hexaaqua iron (III) trinitrate

3 0
2 years ago
The image shows a piston system where gas is compressed. If the uncompressed system is at a standard pressure of 1 atm, what is
MrMuchimi

The answer is 2 atm. I guessed on the problem and got it right. I don’t know the work though.

8 0
3 years ago
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