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denpristay [2]
3 years ago
11

Two students are working together to build two models. Both models will represent the molecular structure of sodium bicarbonate,

NaHCO3 commonly known as baking soda. The students are using toothpicks to represent bonds and jelly beans to represent atoms. Red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms, and blue jelly beans represent sodium atoms, white jellybeans represent hydrogen atoms, like jellybeans our cruise and carbon atoms, and we jellybeans that is an oxygen atoms.
Identify the number of each jelly bean needed to make both models.
Chemistry
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

<em>Note: Since no specific color was stated for oxygen atoms, the answer assigns blue colored jellybeans to represent oxygen atoms.J</em>

Explanation:

Sodium bicarbonate, NaHCO₃ is a compound composed of one atom of sodium, one atom of hydrogen, one atom of carbon and three atoms of oxygen.

Since red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms and blue jellybeans represent oxygen atoms, each of the two students will require the following number of each jellybean for their model of sodium carbonate: One red jellybean, one white jellybean, one black jellybean and three blue jellybeans.

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

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kap26 [50]

Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/mol

The answer is 43 L if I am correct.

3 0
3 years ago
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What is the [H3O+] of a solution with a pH of 8.43?
Yuri [45]
H3O4 is your answer but u should use your chart

8 0
3 years ago
A solution is prepared by dissolving 0.56 g of benzoic acid (C6H5CO2H, Ka ???? 6.4 ???? 10????5) in enough water to make 1.0 L o
garri49 [273]

Answer:

[H⁺] = 6.083x10⁻⁴ M, [C₆H₅OO⁻] = 6.083x10⁻⁴ M, [C₆H₅OOH] = 3.98x10⁻³M, pH = 3.22

Explanation:

Data: we have 0.56 gr of benzoic acid, disolved in 1Lt of water. Kₐ = 6.4x10⁻⁵

M (molar mass) of BA (Benzoic Acid) = 122 g/mol

Then, the inicial concentration is 0.56/122 = 4.59x10⁻³ M

We should consider the equation once it reaches the equilibrium:

C₆H₅COOH ⇄ C₆H₅COO⁻ + H⁺

  C - x                      x              x

And, for the Kₐ:

Kₐ = [H⁺][C₆H₅COO⁻]/[C₆H₅COOH] = x²/(C-x) , where C = 4.59x10⁻³

Then: x² + Kₐx - KₐC = 0

x² + 6.4x10⁻⁵ - 2.9x10⁻⁷ = 0

Resolving this cuadratic equation (remember to use Baskara equation), we obtain:

x = 6.083x10⁻⁴ M

Then: [H⁺] = [C₆H₅COO⁻] = 6.083x10⁻⁴ M

[C₆H₅COOH] = C - x = 3.98x10⁻³ M

pH = -Log [H⁺] = 3.22

7 0
3 years ago
Atoms in a covalent bond are held together by what??
pshichka [43]
<span>
this is because nonmetals. the elements that form covalent bonds want to share the electrons to creat an ocet when this happens the positively charged nucleus has and attraction for the valence, or outer most, electrons of its own atoms as well as for the electrons in the atom that it is trying to share electrons with

</span>
8 0
3 years ago
6)
MrMuchimi

Answer:

(4) Water, stirring, and filtering  

Explanation:

The added water will dissolve the sugar but not the sand. When you filter the mixture, the sand will be trapped in the filter paper and the dissolved sugar will pass through the pores of the paper.

(1) and (2) are wrong. You don't separate a mixture of sugar and sand by adding more sand. Furthermore, neither substance will boil at 100 °C.

(3) is wrong. You can dissolve the sugar in water but, if you boil the water away, the sugar and sand will still be together.

7 0
3 years ago
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