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VMariaS [17]
3 years ago
13

When the forward and reverse paths of a change occur at the same rate,

Chemistry
2 answers:
Zarrin [17]3 years ago
8 0
The correct answer is option B. When the forward and reverse paths of a change occur at the same rate, <span>the system is in equilibrium specifically in dynamic equilibrium.</span> Dynamic equilibrium is the balance in a process that is continuing. It is achieved in a reaction when the forward rate of reaction and the backward rate of reaction is at the same value or equal.

Norma-Jean [14]3 years ago
6 0

Answer:

b. the system is in equilibrium.

Explanation:

Chemical equilibrium occurs when any reaction is reversible, in which there are two possible reactions, one forward (where reactants turn into products) and a reverse one (where products turn reactants). These reactions have the same velocity.

In this state, the rates of forward and reverse reactions are equal, and concentrations of reagents and products remain unchanged.

The velocities within a reversible reaction (in equilibrium) can be represented as follows:

A + B ⇄ C + D

However, this state of equilibrium is vulnerable to some factors, such as changes in pressure, temperature and addition or withdrawal of one or more substances from the system.

These may change one of these velocities and consequently, modify the concentrations of reagents and/or products, causing an equilibrium shift.

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Which structural formula does not represent benzene? a hexagon with nothing drawn inside it a hexagon with a dotted circle drawn
boyakko [2]
Answer:
            <span>A hexagon with nothing drawn inside it does not represent Benzene.

Explanation:

Below attached picture contains structures mentioned in given option.

Structure of Option-A is shown in Red Color.
</span>
Structure of Option-B is shown in Blue Color.

Structure of Option-C is shown in Green Color.

Structure of Option-D is shown in Orange Color.

Result:
          Except Option-A, all structures represent Benzene. Option-A in fact shows the structure of Cyclohexane.

5 0
3 years ago
Read 2 more answers
If the sample contained 2.0 moles of KClO3 at a temperature of 214.0 °C, determine the mass of the oxygen gas produced in grams
Westkost [7]

Answer : The mass of the oxygen gas produced in grams and the pressure exerted by the gas against the container walls is, 96 grams and 1.78 atm respectively.

Explanation : Given,

Moles of KCl_3 = 2.0 moles

Molar mass of O_2 = 32 g/mole

Now we have to calculate the moles of MgO

The balanced chemical reaction is,

2KClO_3\rightarrow 2KCl+3O_2

From the balanced reaction we conclude that

As, 2 mole of KClO_3 react to give 3 mole of O_2

So, 2.0 moles of KClO_3 react to give \frac{2.0}{2}\times 3=3.0 moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(3.0moles)\times (32g/mole)=96g

Therefore, the mass of oxygen gas produced is, 96 grams.

Now we have to determine the pressure exerted by the gas against the container walls.

Using ideal gas equation:

PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\times \frac{RT}{M}\\\\P=\rho\times \frac{RT}{M}

where,

P = pressure of oxygen gas = ?

V = volume of oxygen gas

T = temperature of oxygen gas = 214.0^oC=273+214.0=487K

R = gas constant = 0.0821 L.atm/mole.K

w = mass of oxygen gas

\rho = density of oxygen gas = 1.429 g/L

M = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the ideal gas equation, we get:

P=1.429g/L\times \frac{(0.0821L.atm/mole.K)\times (487K)}{32g/mol}

P=1.78atm

Thus, the pressure exerted by the gas against the container walls is, 1.78 atm.

7 0
3 years ago
Can anyone help with number 8.
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A tornado! I think or it could be rain
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What is the smallest part of an element that has all the properties of that element?
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The smallest participle of an element is called an atom
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They drill too deep and find lava
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