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4 years ago

When the forward and reverse paths of a change occur at the same rate,

2 answers:

8 0

The correct answer is option B. When the forward and reverse paths of a change occur at the same rate, <span>the system is in equilibrium specifically in dynamic equilibrium.</span> Dynamic equilibrium is the balance in a process that is continuing. It is achieved in a reaction when the forward rate of reaction and the backward rate of reaction is at the same value or equal.

Norma-Jean [14]4 years ago

6 0

Answer:

b. the system is in equilibrium.

Explanation:

Chemical equilibrium occurs when any reaction is reversible, in which there are two possible reactions, one forward (where reactants turn into products) and a reverse one (where products turn reactants). These reactions have the same velocity.

In this state, the rates of forward and reverse reactions are equal, and concentrations of reagents and products remain unchanged.

The velocities within a reversible reaction (in equilibrium) can be represented as follows:

A + B ⇄ C + D

However, this state of equilibrium is vulnerable to some factors, such as changes in pressure, temperature and addition or withdrawal of one or more substances from the system.

These may change one of these velocities and consequently, modify the concentrations of reagents and/or products, causing an equilibrium shift.

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NaOH is an Arrhenius base because it increases the concentration of hydroxide ions when dissolved in solution.

Licemer1 [7]

The answer is true, NaOH is and Arrhenius base.

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3 years ago

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Measurements include

Keith_Richards [23]

There’s lots of measurements. (m, kg, s, mol, cm, in, mm) etc

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4 years ago

Once the concentration of the common ion is increased: Select the correct answer below: the solubility of the ionic solid increa

Vaselesa [24]

Answer:

the solubility of the ionic solid decreases

Explanation:

If a salt MX is added to an aqueous solution containing the solute AX, the X^- ion is common to both of the salts. The presence of X^- in the solution will suppress the dissolution of AX compared to the solubility of AX in pure water. This observation is known as common ion effect in chemistry.

The origin of common ion effect is based on Le Chatelier's principle. The addition of a solute will drive the equilibrium position towards the left hand side.

3 0

3 years ago

Bismuth oxide reacts with carbon to form bismuth metal:

lesya692 [45]

Answer:

(a) 1.92 moles of Bi produced.

(b) 80.6 grams

Explanation:

Balanced equation: Bi2O3(s) + 3C(s) → 2Bi(s) + 3CO(g)

1st find moles of Bi2O3:

Bi2O3 has Mr of 466 and mass of 447 g

$\hookrightarrow moles = \frac{mass}{Mr}$

$\hookrightarrow moles = \frac{447}{466}$

$\hookrightarrow moles = 0.959227$

2nd find moles of Bi:

Bi2O3 : 2Bi

→ 1 : 2 ------ this is molar ratio.

→ 0.959227 : (0.959227)*2

→ 0.959227 : 1.91845

→ 0.959227 : 1.92

Therefore 1.92 moles of Bi was produced.

3rd Find moles of 3CO:

Bi2O3 : 3CO

1 : 3

0.959227 : (0.959227 )*3

0.959227 : 2.87768

3CO has 2.87768 moles and we know the Mr is 28.

$\hookrightarrow mass = moles * Mr$

$\hookrightarrow mass = 2.87768 * 28$

$\hookrightarrow mass =80.575$ g

Therefore 80.575 grams of CO was produced.

8 0

2 years ago

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Determine the ΔH for the following reaction 2NH3 + 5/2O2 = 2NO(g) + 3 H2O(g)

beks73 [17]

The enthalpy change, ΔH for the following reaction $2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)$ is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

Enthalpy change, ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

$2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)$

$\Delta{H_{f}\:of\:NO = 90.25 kJ; \Delta{H_{f}\:of\:H_{2}O =-241.82kJ; \Delta{H_{f}\:of\:NH_{3} =-46.1 kJ; \Delta{H_{f}\:of\:O_{2} =0$

$\Delta{H_{f}\:of\:rxn = (90.25*2)+(-241.82*3)-( -46.1*2)= -452.76\:kJ$

Therefore, the enthalpy change, ΔH for the following reaction $2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)$ is -452.76 kJ.

Learn more about enthalpy change at: brainly.com/question/14047927

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4 0

2 years ago

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