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skad [1K]
4 years ago
5

Need help ASAP !!

Chemistry
1 answer:
Kitty [74]4 years ago
6 0

Answer:

it's a segment

Explanation:

it has multiple end points

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Which statement best summarizes what happens during cellular respiration?
morpeh [17]

Answer:

A

Explanation:

B and D have to do with plants

and C has nothing to do with cellular resporation.

8 0
3 years ago
Read 2 more answers
What is one use for halogens?
Ahat [919]

The correct answer is D. Light bulbs

Explanation:

In chemistry, halogens are a group of elements characterized for being non-metallic elements (they cannot conduct heat or electricity), and for forming salts. In terms of uses, halogens had been used mainly as part of disinfectants, as well as, in the production of light bulbs and lamps. This last application implies small quantities of halogens such as iodine are used in the mechanism of bulbs or lamps and this is a better option than other elements as it increases the life of the bulb and makes bulbs to a whither color. According to this, one use of halogens is light bulbs.

8 0
3 years ago
Please help with this question and explain too
nikitadnepr [17]
Formula of density is mass divided by volume.

8 0
3 years ago
Neon atom can exist freely in mature but sodium atom can not,why
andrew-mc [135]

Answer:-

Neon is a noble gas. Neon with an electronic configuration of 2,8 has 8 electrons in it's outermost shell or valence shell.

According to the Octet theory if an element has eight electrons in it's valence shell then it is stable and does not undergo reaction. Thus Neon does not need to react and can exist freely in nature.

Sodium with an electronic configuration of 2,8,1 has 1 electron in it's valence shell. As per octet rule, it is not stable and it must lose that 1 electron to become stable.

In order to lose that 1 electron sodium must react with other substances. Hence sodium cannot exist freely in nature.

5 0
3 years ago
Phosgene has the elemental compositions of 12.14% carbon, 16.17 % oxygen, and 71.69% chlorine by mass.
inessss [21]

Answer:

a) COCl₂.

b) The molecular formula is COCl₂.

Explanation:

To obtain empirical formula of phosgene you should divide elemental compositions over atomic mass of each atom, and divide these results between the smallest, thus:

C = 12,14%/12,01 = 1,01

O = 16,17%/16 = 1,01

Cl = 71,69%/35,45 = 2,02

Empirical formula:

C = 1,01/1,01 = 1

O = 1,01/1,01 = 1

Cl = 2,02/1,01 = 2

C₁O₁Cl₂ ≡ COCl₂

b) You need to find the molar mass of the empirical formula to determine the ratio of the real formula, thus:

1×C 12,01g/mol =

1×O 16 g/mol =

2×Cl 35,35g/mol = 98,91g/mol

As real molecular mass is 98,9 g/mol. The molecular formula: COCl₂

I hope it helps!

6 0
4 years ago
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