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2 years ago

For this question, you will need to submit a picture of your work in order to receive credit for the proper calculation.

Chemistry

2 answers:

Alex Ar [27]2 years ago

8 0

Answer above is correct !

umka21 [38]2 years ago

6 0

O.85 x 2 x 9.85 + 4 this is the answer please mark brainliest

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Ammonia NH3 is a common ingredient. If you have a cleaning agent containing 3.47 mol NH3, how many grams of NH3 are in the clean

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NH3 has a Molar mass of 17g
3.47 * M(NH3) = 58.99g of NH3 in the cleaning agent

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3 years ago

56. When a person is not in touch with reality, they might have

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D: Schizophrenia. The individual that’s diagnoses with Schizophrenia tends to be disconnected with reality, leading to breakdowns in the world around them. A man sees a crowd of screaming, aggressive ghosts when it’s only a crowd of people waiting for a bus.

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3 years ago

Refer to aqueous solutions containing 1:1 mole ratios of the following pairs of substances. Assume all concentrations are 1 M.

LekaFEV [45]

Answer:

c) HCl and NaCl

Explanation:

Since all the solutions are on a 1:1 mole ratio the comparison is straight forward.

The lowest pH will be for solution c) which has a strong acid, HCl, which ionizes 100 % and the neutral salt NaCl (which is neutral since it is derived from the reaction of the strong acid HCl and the strong base NaOH).

Solutions a) and b) are buffers of the weak base NH₃ and its conjugate acid NH₄⁺ and weak acid H₃PO₄ and its conjugate weak base NaH₂PO₄ respectively.

Solution c) is a basic solution being a mixture of the weak base NH₃ and the strong base NaOH

Solution e) is a mixture of a weak base NH₂ and weak acid HC₂H₃O₂

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3 years ago

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Question 7 (1 point)

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Answer:

Cell membranes (plasma membranes) help organisms maintain homeostasis by controlling what substances may enter or leave cells.

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3 years ago

A cup of gold colored metal beads was measured to have a mass 425 grams. By water displacement, the volume of the beads was calc

Troyanec [42]

Given parameters;

Mass of gold colored metal beads = 425g

Volume of water displaced by beads = 48.0cm³

Unknown;

Identity of the metal = ?

Given densities;

Gold: 19.3 g/mL

Copper: 8.86 g/mL

Bronze: 9.87 g/mL

Density is an intensive property of any substance. This implies that we can use the density of any substance to identify it.

Density can be defined as the mass per unit volume of a substance. Every substance has a unique mass per volume.

Mathematically;

Density = $\frac{mass}{volume}$

where mass is in kg or g

volume is in m³ or cm³

To find the density, we must know the mass and volume.

In this problem, the volume of the gold metal beads is the same as the volume of water displaced. This is a way to measure volume of solids.

Since the volume is given in cm³, and we are comparing with choices that have units in g/mL, we simply convert the volume in cm³ to mL

1cm³ = 1mL³

So therefore, volume of gold colored metal is 48mL

Now input the parameters given and solve for the density;

Density = $\frac{425g}{48mL }$ = 8.85g/mL

From the given densities, we clearly see that copper is the metal since they both of similar densities.

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3 years ago