Answer:
- Empirical:

- Molecular:

Explanation:
Hello,
In this case, based on the information regarding the combustion, the moles of carbon turn out:

Moreover, the moles of hydrogen:

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

Which is hexane.
Best regards.
Answer:
C6H12O6 + 6O2 → 6CO2 + 6H2O
Explanation:
Cellular respiration occurs in the mitochondria of cells. It is a process in which sugar is combined with oxygen to produce energy, water and carbon dioxide. This is the major process by which energy is released in living organisms.
Aerobic respiration involves a series of chemical reactions. These reactions commence with sugar and oxygen then it produces carbon dioxide and water according to the reaction equation; C6H12O6 + 6O2 → 6CO2 + 6H2O.
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
I think it is the more fertile the soil
The particular reaction that represents the oxidation of Mg metal would be the following:
Mg => Mg+2 + 2e-
This is the half reaction of the oxidation of the magnesium metal, another charged species would need to receive it to become reduced or gain the 2 electrons lost.