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KiRa [710]
3 years ago
12

How many grams are equal to 413 kg

Chemistry
2 answers:
vladimir2022 [97]3 years ago
7 0

Answer:

413,000

Explanation: That's because 1 kg equals to 1,000 grams.

notka56 [123]3 years ago
3 0

Answer:

413,000 grams

Explanation:

You might be interested in
When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

6 0
3 years ago
Living things respire to stay alive. In the mitochondria, sugar is combined with oxygen to produce energy, water and carbon diox
olya-2409 [2.1K]

Answer:

C6H12O6 + 6O2 → 6CO2 + 6H2O

Explanation:

Cellular respiration occurs in the mitochondria of cells. It is a process in which  sugar is combined with oxygen to produce energy, water and carbon dioxide. This is the major process by which energy is released in living organisms.

Aerobic respiration involves a series of chemical reactions.  These reactions commence with sugar and oxygen then it produces  carbon dioxide and water according to the reaction equation; C6H12O6 + 6O2 → 6CO2 + 6H2O.

8 0
2 years ago
Read 2 more answers
NEED HELP ASAP NOT DIFFICULT
Burka [1]
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
5 0
2 years ago
Read 2 more answers
The higher the number of living organisms in an area, the ___ fertile the soil.<br> Less, more.
goldenfox [79]
I think it is the more fertile the soil
4 0
3 years ago
Magnesium loses 2 electrons. Which reaction represents the oxidation of magnesium?
alexdok [17]
The particular reaction that represents the oxidation of Mg metal would be the following:

Mg => Mg+2 + 2e-

This is the half reaction of the oxidation of the magnesium metal, another charged species would need to receive it to become reduced or gain the 2 electrons lost.
6 0
3 years ago
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