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ycow [4]
3 years ago
15

In Exercises 29 and 30, describe the possible echelon forms of the standard matrix for a linear transformation T . Use the notat

ion of Example 1 in Section 1.2. 29. T W R3 ! R4 is one-to-one. 30. T W R4 ! R3 is onto.
Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

<u>note:</u>

<u><em>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</em></u>

Download docx
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Find the area of a triangle whose sides are 5 m, 6 m and 9m,( use root 2 =-1.41 m)​
dlinn [17]

The area of the triangle is 14.1 square meters

<h3>How to determine the triangle area?</h3>

The side lengths are given as:

5m, 6m and 9m

Calculate the semi-perimeter (s) using

s = (5 + 6 + 9)/2

Evaluate

s = 10

The area is then calculated as:

Area = \sqrt{s(s -a)(s-b)(s-c)

This gives

Area = \sqrt{10 * (10 -5)(10-6)(10-9)

Evaluate the products

Area = \sqrt{200

Evaluate the exponent

Area = 14.1

Hence, the area of the triangle is 14.1 square meters

Read more about areas at:

brainly.com/question/27683633

#SPJ1

4 0
2 years ago
A line has a slope of -7 and includes the points (7,p) and (8,-3) what is the value of p?
Whitepunk [10]
It’s 7 and -7 to easy for me
4 0
3 years ago
Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.
lilavasa [31]

Answer:

y = -13x + 55

Step-by-step explanation:

perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

3 = -13 (4) + c

3 = -52 + c

3 + 52 = c

55 = c

c = 55

now we rewrite again the c and the m to become a complete equation : y = -13x + 55

5 0
3 years ago
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
sdas [7]

Answer:

a

    n=  75, 582

b

  n=    2300

c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
3 years ago
John shot a toy rocket into the air. Consider the graph below which shows the relationship between the height of the rocket from
EleoNora [17]
<h2>The height of the rocket increases for some time and then decreases for some time.</h2>

The height from the ground increases from 4 to 26, then decreases from 26 to 0.

Why the others are wrong.

A. The height of the rocket changes at a constant rate for the entire time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

C. The height of the rocket remains constant for some time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

D. The height of the rocket decreases for some time and then increases for some time.

This implies the graph decreases first then increases. However, the rocket will increase, then decrease.

5 0
3 years ago
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