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ycow [4]
3 years ago
15

In Exercises 29 and 30, describe the possible echelon forms of the standard matrix for a linear transformation T . Use the notat

ion of Example 1 in Section 1.2. 29. T W R3 ! R4 is one-to-one. 30. T W R4 ! R3 is onto.
Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

<u>note:</u>

<u><em>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</em></u>

Download docx
You might be interested in
What is the value of a in the equation 5a -10b = 45 when b = 3
leva [86]
Salutations!

5a-10b = 45

value of b = 3

Multiply 10 and 3

10*3=30

Now, you can solve the equation --

5a-30=45

separate the variables aside, and the numbers aside.

5a=45 +30

5a=75

a=75/5

a=15

Hope I helped (:

Have a great day!
6 0
3 years ago
Solve the equation cos (x/2) = cos x + 1. what are the solutions on the interval 0° ≤ x &lt; 360°?
Sedbober [7]

Answer:

Step-by-step explanation:

cos (x/2)=cos x+1

cos (x/2)=2cos ²(x/2)

2 cos²(x/2)-cos (x/2)=0

cos (x/2)[2 cos (x/2)-1]=0

cos (x/2)=0=cos π/2,cos (3π/2)=cos (2nπ+π/2),cos(2nπ+3π/2)

x/2=2nπ+π/2,2nπ+3π/2

x=4nπ+π,4nπ+3π

n=0,1,2,...

x=π,3π

or x=180°,540°,...

180°∈[0,360]

so x=180°

or

2cos(x/2)-1=0

cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)

x/2=360n+60,360n+300

x=720n+120,720n+300

n=0,1,2,...

x=120,300,840,1020,...

only 120° and 300° ∈[0,360°]

Hence x=120°,180°,300°

7 0
2 years ago
Before she started hiking, Jessica’s altimeter read +250 meters. She climbed 200 meters and reached point A, which is at an elev
suter [353]

Point A altimeter reading: +450

Point B altimeter reading: -50

7 0
3 years ago
Researchers recorded that a certain bacteria population declined from 800,000 to 500,000 in 6 hours after the administration of
kupik [55]

Answer:

We can assume that the decline in the population is an exponential decay.

An exponential decay can be written as:

P(t) = A*b^t

Where A is the initial population, b is the base and t is the variable, in this case, number of hours.

We know that: A = 800,000.

P(t) = 800,000*b^t

And we know that after 6 hours, the popuation was 500,000:

p(6h) = 500,000 = 800,000*b^6

then we have that:

b^6 = 500,000/800,000 = 5/8

b = (5/8)^(1/6) = 0.925

Then our equation is:

P(t) = 800,000*0.925^t

Now, the population after 24 hours will be:

P(24) = 800,000*0.925^24 = 123,166

5 0
3 years ago
A train traveled 325 miles in 5hrs. What was the trains average rate of speed in miles per hr ?
Leya [2.2K]

Hi there!

To find the average speed of a moving object all you need to do is divide the distance traveled by the object by amount of time it took the object to reach its final destination. So for this problem it would go like this:

325 ÷ 5 = 65

So for this problem in particular the answer is 65 MPH was the average speed of the train.

Your friend, ASIAX

5 0
3 years ago
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