Suppose you were to read about a scientific statement based on data from hundreds of years of research and observation that appl
1 answer:
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Answer:
Complete ionic: .
Net ionic: .
Explanation:
Start by identifying species that exist as ions. In general, such species include:
- Soluble salts.
- Strong acids and strong bases.
All four species in this particular question are salts. However, only three of them are generally soluble in water: ,
, and
. These three salts will exist as ions:
- Each
formula unit will exist as one
ion and one
ion.
- Each
formula unit will exist as one
ion and two
ions (note the subscript in the formula
.)
- Each
formula unit will exist as one
On the other hand, is generally insoluble in water. This salt will not form ions.
Rewrite the original chemical equation to get the corresponding ionic equation. In this question, rewrite ,
, and
(three soluble salts) as the corresponding ions.
Pay attention to the coefficient of each species. For example, indeed each formula unit will exist as only one
ion and one
ion. However, because the coefficient of
in the original equation is two,
alone should correspond to two
ions and two
ions.
Do not rewrite the salt because it is insoluble.
.
Eliminate ions that are present on both sides of this ionic equation. In this question, such ions include one unit of and two units of
. Doing so will give:
.
Simplify the coefficients:
.
Answer:
The temperature of the air at this given elevation will be 53.32425°C
Explanation:
We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.
Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm
We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T ),
PV
/ T
= P
V
/ T
,
T = P
V
T
/ P
V
,
T = 0.73 atm
1.8 L
298.15 K / 1 atm
1.2 L = ( 0.73
1.8
298.15 / 1
1.2 ) K = 326.47425 K,
T = 326.47425 K = 53.32425 C