The answer is in the attachment below:
If air contains 78% Nitrogen by volume, what is the solubility of nitrogen in water at 25 degree celisus
1 answer:
The solubility of nitrogen in water at 25 °C= 4.88 x 10⁻⁴ mol/L
<h3>Further explanation</h3>Given
78% Nitrogen by volume
Required
The solubility of nitrogen in water
Solution
Henry's Law states that the solubility of a gas is proportional to its partial pressure
Can be formulated
S = kH. P.
S = gas solubility, mol / L
kH = Henry constant, mol / L.atm
P = partial gas pressure
In the standard 25 C state, the air pressure is considered to be 1 atm, so the partial pressure of N₂ -nitrogen becomes:
Vn / Vtot = Pn / Ptot
78/100 = Pn / 1
Pn = 0.78 atm
Henry constant for N₂ at 25 °c = 1600 atm/mol.L=6.25.10⁻⁴ mol/L.atm
The solubility :
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Answer : The theoretical yield of HCl is, 56.1735 grams
Explanation : Given,
Mass of = 60 g
Mass of = 37.5 g
Molar mass of = 117 g/mole
Molar mass of = 18 g/mole
Molar mass of = 36.5 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 mole of react with 3 mole of
So, 0.513 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of .
As, 1 mole of react to give 3 moles of
So, 0.513 moles of react to give
moles of
Now we have to calculate the mass of .
Therefore, the theoretical yield of HCl is, 56.1735 grams