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<u>Answer:</u> The pressure of NO and in the mixture is 0.58 atm and 0.024 atm respectively.
<u>Explanation:</u>
We are given:
Equilibrium partial pressure of = 0.29 atm
For the given chemical equation:
Initial: a
At eqllm: a-2x 2x x
Calculating for the value of 'x'
Equilibrium partial pressure of NO = 2x = 2(0.29) = 0.58 atm
Equilibrium partial pressure of = a - 2x = a - 2(0.29) = a - 0.58
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
Neglecting the value of a = 0.555 because it cannot be less than the equilibrium concentration.
So,
Equilibrium partial pressure of = (a - 0.58) = (0.604 - 0.58) = 0.024 atm
Hence, the pressure of NO and in the mixture is 0.58 atm and 0.024 atm respectively.