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jekas [21]
3 years ago
5

a pelican flying along a horizontal path drops a fish from a height of 5.4m. the fish travels 8.0m horizontally before it hits t

he water below. what is the pelican's initial spee.(vx=7.6
Physics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

7.0 m/s

Explanation:

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Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice.

Explanation:

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What effects do coil of wire on a compass after it has been connected to a battery​
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What is the definition of physical change
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3 years ago
You are traveling on an airplane. The velocity of the plane with respect to the air is 110.0 m/s due east. The velocity of the a
Mice21 [21]
1. Vpa = 180m/s. @ 0 deg.
  Vag = 40m/s @ 120 deg,CCW.


<span> Vpg = Vpa + Vag,
 Vpg = (180 + 40cos120) + i40sin120,
  Vpg = 160 + i34.64,
 Vpg=sqrt((160)^2 + (34.64)^2)=163.7m/s.
</span>
<span>2. tanA = Y / X = 34.64 / 160 = 0.2165,
  A = 12.2 deg,CCW. = 12.2deg. North of East. </span>

3.  1 hr = 3600s. <span>d = Vt = 163.7m/s * 3600s = 589,320m.

hope this helps</span>
8 0
2 years ago
A child slides down a hill on a toboggan with an acceleration of 1.8 m/s^2. If she starts at rest, how far has she traveled in :
DENIUS [597]

Explanation:

It is given that,

The acceleration of the toboggan, a=1.8\ m/s^2

Initial speed of the toboggan, u = 0

We need to find the distance covered by the toboggan. Using the second equation of motion as :

s=ut+\dfrac{1}{2}at^2

At t = 1 s

s=\dfrac{1}{2}\times 1.8\times 1^2

s_1=0.9\ m

At t = 2 s

s=\dfrac{1}{2}\times 1.8\times 2^2

s_2=3.6\ m

At t = 3 s

s=\dfrac{1}{2}\times 1.8\times 3^2

s_3=8.1\ m

Hence, this is the required solution.

4 0
3 years ago
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