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Bezzdna [24]
3 years ago
9

Which type of mixture could this illustration represent?

Physics
2 answers:
Oksanka [162]3 years ago
4 0

Answer:

A homogeneous mixture

Explanation:

Helga [31]3 years ago
4 0

Answer: Option (B) is the correct answer.

Explanation:

A mixture in which solute particles are unevenly distributed in a solvent is known as a heterogeneous mixture.

For example, sand in water is a heterogeneous mixture.

Whereas a mixture in which solute particles are evenly or uniformly distributed in a solvent is known as a homogeneous mixture.

For example, salt in water is a homogeneous solution.

Thus, we can conclude that the given mixture shows that molecules are uniformly distributed in the solution.

Therefore, the given illustration represents homogeneous type of mixture.

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4 0
3 years ago
While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the
ANTONII [103]

Well, you see, I don't think Alana really is the reference frame. 
Call me paranoid, but I think you changed the reference frame
during the question, and didn't tell us.

In which reference frame is the 19 km/hr measured ?
It CAN'T be Alana's reference frame.  Your own reference
frame moves along with you, and you can't move in it, even
if your name is Alana.

If Alana is the reference frame, and she throws the tennis ball
at 11 km/hr, then the speed of the ball is 11 km/hr in Alana's
reference frame.  Her reference frame moves with  her, so
it makes no difference how fast she is skateboarding in any
other reference frame, who she throws the ball at, or whether
or not he sees it coming and catches it.

Yes, this stuff can get confusing.  And if you think it's bad now,
wait till you start reading some of Prof. Einstein's stuff, where
two people in the same reference frame can watch the same
tennis ball, and not even agree on how fast it's moving, because
THEY're both moving and their own motion makes their rulers
and clocks change !  So they measure different speeds, and
they're both right !

But I got distracted.  I'm sorry.  The point I'm trying to make,
right now when you're just starting to learn reference frames,
is that EVERY time you say a speed, you have to tell which
reference frame the speed is in.  Because, as you're starting
to learn, the same object can have a different speed in every
reference frame.

And, just in case you're thinking about this later today
and you want to ask "Which one is the REAL speed  ?" . . .
THAT's the whole point of learning about reference frames !
There is NO SUCH THING as REAL speed.  It ALWAYS
depends on which reference frame it's measured in.  They're
all different, they're all real, and they're all correct.

5 0
3 years ago
Read 2 more answers
A stone is thrown straight up. While the stone is rising: Group of answer choices its acceleration is upward and decreasing its
leva [86]

A stone is thrown straight up. While the stone is rising: Group of answer choices its acceleration is upward and decreasing its acceleration is upward and constant its acceleration is upward and increasing its acceleration is zero None of the available answers are correct. its <u>acceleration </u><u>is zero</u>

<h3>What is acceleration ?</h3>

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. It is a vector quantity to accelerate (in that they have magnitude and direction). The direction of the net force acting on an object determines the direction of its acceleration.

According to Newton's Second Law, the amount of an object's acceleration depends on two factors: the net balance of all external forces acting on the object; the magnitude of the acceleration is directly proportional to the net resulting force. For instance, when a vehicle begins at rest (zero velocity in an inertial frame of reference) and moves straight ahead at increasing speeds, it is accelerating in the direction of travel.

To learn more about acceleration  from the given link:

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7 0
2 years ago
A ball starts from rest and accelerates at 0.460 m/s2 while moving down an inclined plane 8.85 m long. When it reaches the botto
Ivahew [28]

Answer:

V=2.8534m/s \approx 3m/s

Explanation:

From the question we are told that

Acceleration a=0.460m/s

Distance traveled S_1=8.5m

Distance traveled S_2=15.6m

Generally the velocity of the ball at the bottom of the first plane V is mathematically given by

v^2=2as

v=\sqrt{2as}

V=\sqrt{2*0.460*8.85}

V=2.8534m/s \approx 3m/s

6 0
3 years ago
Two 10 kg pucks head straight towards each other with velocities of 10 m/s and -20 m/s. They collide and stick together. Calcula
RUDIKE [14]

The final velocity of the two pucks is -5 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum.

In fact, in absence of external force, the total momentum of the two pucks before and after the collision must be conserved - so we can write:

m_1 u_1 + m_2 u_2 = (m_1 +m_2)v

where

m_1 = m_2 = m = 10 kg is the mass of each puck

u_1 = 10 m/s is the initial velocity of the 1st puck

u_2 = -20 m/s is the initial velocity of the 2nd puck

v is the final velocity of the two pucks sticking together

Re-arranging the equation and solving for v, we find:

mu_1 + mu_2 = (m+m)v\\u_1 + u_2 = 2v\\v=\frac{u_1+u_2}{2}=\frac{10-20}{2}=-5 m/s

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8 0
3 years ago
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