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3 years ago

How do lenses and mirrors compare in their interactions with light?

Physics

2 answers:

slamgirl [31]3 years ago

7 0

D. lenses focus light , mirrors do not

Alisiya [41]3 years ago

4 0

Answer:

C. lenses refract light; mirrors do not

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The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of

motikmotik

Explanation:

It is given that, the force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed such that,

$F\propto \dfrac{mgv^2}{r}$

$F=\dfrac{kmgv^2}{r}$

mg is the weight of the car

r is the radius of the curve

v is the speed of the car

Case 1.

F = 640 pounds

Weight of the car, W = mg = 2600 pound

Radius of the curve, r = 650 ft

Speed of the car, v = 40 mph

$640=\dfrac{k(2600)(40)^2}{650}$

k = 0.1

Case 2.

Radius of the curve, r = 750 ft

Speed of the car, v = 30 mph

$F=\dfrac{0.1\times 2600\times (30)^2}{750}$

F = 312 N

Hence, this is the required solution.

6 0

3 years ago

If two solutions have unequal concentrations of a solute, the solution with the lower concentration is called

marta [7]

Obviouskly lower concentrstion

6 0

3 years ago

A boy holds a heavy package for one hour. He is very tired but has not done any work. Explain why he did not do any work.

Feliz [49]

Answer:he's not applying force or motion

Explanation:

p=f & m

5 0

2 years ago

Which scale measures the amount of damage after an earthquake?

OLga [1]

Mercalli Intensity Scale:

<em> is a seismic intensity scale used for measuring the intensity of an earthquake. ... It is distinct from the moment magnitude (Mw) usually reported for an earthquake, which is a measure of the energy released (sometimes misreported as the Richter magnitude, ML).</em>

6 0

3 years ago

Read 2 more answers

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent ho

faltersainse [42]

Answer:

Explanation:

Let mass of cylinder be M

Moment of inertia of cylinder

= 1/2 M R² r is radius of cylinder

If radius of equivalent hoop be k

Mk² = 1/2 x MR²

k = R / √2

1.2 / 1.414

Radius of gyration = 0.848 m

b )

moment of inertia of spherical shell

= 2 / 3 M R²

Moment of inertia of equivalent hoop

Mk²

Mk² = 2 / 3 M R²

k = √2/3 x R

= .816 X 1.2

Radius of gyration = .98 m

c )

Moment of inertia of solid sphere

= 2/5 M R²

Moment of inertia of equivalent hoop

= Mk²

Mk² = 2/5 M R²

k √ 2/5 R

Radius of gyration = .63 R

6 0

4 years ago