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PSYCHO15rus [73]
3 years ago
15

Technician A says when diagnosing an overheating hydraulic system, be sure that the oil cooler is not plugged and the cooler’s f

an is working. Technician B says running the hydraulic system at a lower operating temperature will reduce the possibly of oil oxidation. Who is correct?
Physics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

Tech B is correct and Tech A is incorrect.

Explanation:

Here Tech A is wrong because when diagnosing an overheating hydraulic system, it is not necessary to un plugg the oil cooler rather it should be plugged to for proper diagnosis.

Technician B says running the hydraulic system at a lower operating temperature will reduce the possibly of oil oxidation is correct statement because at temperature oil's physical as well as chemical property tend to change.

Hence, Tech B is correct and Tech A is incorrect.

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4 years ago
Unlike other states of matter, what expand to fill their containers
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gas

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3 years ago
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To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi
abruzzese [7]

Answer:

(a) 5.73 * 10¹³ m/s²

(b) 4.99 * 10⁵ m/s

Explanation:

(a) We know that Electrical force is the product of electric charge and electric field:

F = qE

We also know that Force is the product of mass and acceleration:

F = ma

Therefore, equating both of them:

ma = qE

Acceleration, a, will be:

a = (qE) / m

Electric charge of a positron = 1.602 * 10^(-19) C

Mass of a positron = 9.11 * 10^(-31) kg

Acceleration will be:

a = (1.602 * 10^(-19)) * 9.11 * 10^(-31)) / 326

a = 5.73 * 10¹³ m/s²

(b) Acceleration is the time rate of change of velocity. It is given as:

a = v/t

Velocity, v, will then be:

v = a * t

Time, t = 8.7 * 10^(-9) s

Therefore, velocity will be:

v = 5.73 * 10^(13) * 8.7 * 10^(-9)

v = 49.85 * 10⁴ m/s = 4.99 * 10⁵ m/s

7 0
3 years ago
The velocity of a particle traveling in a straight line is given by v = (6t - 3t²) m/s, where t is in seconds. If s = 0 when t =
qaws [65]

Answer

given,

v = (6 t - 3 t²) m/s

we know,

v = \dfrac{dx}{dt}

a = \dfrac{dv}{dt}

position of the particle

dx = v dt

integrating both side

\int dx = (6t - 3 t^2)\int dt

 x = 3 t² - t³

Position of the particle at t= 3 s

 x = 3  x 3² - 3³

 x = 0 m

now, particle’s deceleration

a = \dfrac{dv}{dt}

a = \dfrac{d}{dt}(6t - 3 t^2)

  a = 6 - 6 t

at t= 3 s

    a = 6 - 6 x 3

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distance traveled by the particle

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at t = 0 x = 0

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D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s

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average speed of the particle

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8 0
3 years ago
What is the speed of a car that traveled 500 meter in 30 seconds?
GenaCL600 [577]
<h2>Greetings!</h2>

To find speed, you need to remember the formula:

Speed = distance ÷ time

So plug the given values in:

500 ÷ 30 = 16.66

<h3>So the speed is 16.66m/s (metres per second)</h3>
<h2>Hope this helps!</h2>
3 0
3 years ago
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