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PSYCHO15rus [73]
3 years ago
15

Technician A says when diagnosing an overheating hydraulic system, be sure that the oil cooler is not plugged and the cooler’s f

an is working. Technician B says running the hydraulic system at a lower operating temperature will reduce the possibly of oil oxidation. Who is correct?
Physics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

Tech B is correct and Tech A is incorrect.

Explanation:

Here Tech A is wrong because when diagnosing an overheating hydraulic system, it is not necessary to un plugg the oil cooler rather it should be plugged to for proper diagnosis.

Technician B says running the hydraulic system at a lower operating temperature will reduce the possibly of oil oxidation is correct statement because at temperature oil's physical as well as chemical property tend to change.

Hence, Tech B is correct and Tech A is incorrect.

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A block of wood measuring 2.75 cm x 4.80 cm x 7.50 cm has a mass of 84.0 g. will the block of wood sink or float in water?
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The volume of the block of wood is given by length × width ×height
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3 years ago
You are at the carnival with you your little brother and you decide to ride the bumper cars for fun. You each get in a different
Aliun [14]

Answer:

<em>a) The equation is </em>(m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

<em>b) Your velocity after collision is 2.64 m/s</em>

<em>c) The force you felt is 7392 N</em>

<em>d) you and your brother undergo an equal amount of acceleration</em>

<em></em>

Explanation:

Your mass m_{y} = 60 kg

your brother's mass m_{b} = 30 kg

mass of the car m_{c} = 80 kg

your initial speed u_{y} = 0 m/s (since you've not started moving yet)

your brother's initial velocity u_{b} = 3 m/s

your final speed v_{y} after collision = ?

your brother's final speed v_{b} after collision = ?

a) equations you need to use to figure out how fast you and your brother are moving after the collision is

(m_{y}+m_{c} )u_{y} + (m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

but u_{y} = 0 m/s

the equation reduces to

(m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

b) if your little brother reverses with velocity of 0.36 m/s it means

v_{b} = -0.36 m/s (the reverse means it travels in the opposite direction)

then, imputing values into the equation, we'll have

(m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

(30 + 80)3 = (60 + 80)v_{y} + (30 + 80)(-0.36)

330 = 140v_{y} - 39.6

369.6 = 140v_{y}

v_{y} = 369.6/140 = <em>2.64 m/s</em>

This means you will also reverse with a velocity of 2.64 m/s

c) your initial momentum = 0  since you started from rest

your final momentum = (total mass) x (final velocity)

==>  (60 + 80) x 2.64 = 369.6 kg-m/s

If the collision lasted for 0.05 s,

then force exerted on you = (change in momentum) ÷ (time collision lasted)

force on you = ( 369.6 - 0) ÷ 0.05 =<em> 7392 N</em>

<em></em>

d) you changed velocity from 0 m/s to 2.64 m/s in 0.05 s

your acceleration is (2.64 - 0)/0.05 = 52.8 m/s^2

your brother changed velocity from 3 m/s to 0.36 m/s in 0.05 s

his deceleration is (3 - 0.36)/0.05 = 52.8 m/s

<em>you and your brother undergo an equal amount of acceleration. This is because you gained the momentum your brother lost</em>

<em></em>

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dalvyx [7]

Answer:

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