Answer : The value of new volume is, 50.0 mL
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
or,
where,
= initial pressure at STP = 1 atm
= final pressure = 4.00 atm
= initial volume at STP = 200.0 mL
= final volume = ?
Now put all the given values in the above equation, we get:
Therefore, the value of new volume is, 50.0 mL
An electron can be added to halogen atom to force a halide ion with 8 valence electrons
<h3>What is an atom?</h3>
An atom can be defined as the smallest part of an element which can take part in a chemical reaction.
However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons
So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons
Learn more about halogens:
brainly.com/question/18276987
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Answer:I would copy and past but that’s a lot of work just read it
Explanation:
Answer:
Part A = The mass of sulfur is 6.228 grams
Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams
Explanation:
Part A
Step 1: Data given
A mixture of carbon and sulfur has a mass of 9.0 g
Mass of the product = 27.1 grams
X = mass carbon
Y = mass sulfur
x + y = 9.0 grams
x = 9.0 - y
x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6
(9 - y)*(44.01/12.01) + y(64.07/32.07)
(9-y)(3.664) + y(1.998)
32.976 - 3.664y + 1.998y = 22.6
-1.666y = -10.376
y = 6.228 = mass sulfur
x = 9.0 - 6.228 = 2.772 grams = mass C
The mass of sulfur is 6.228 grams
Part B
Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).
Calculate moles of 1 silver atom
Moles = 1/ 6.022*10^23
Moles = 1.66*10^-24 moles
Mass = moles * molar mass
Mass = 1.66*10 ^-24 moles *107.87
Mass = 1.79 * 10^-22 grams
The mass of 1 silver atom is 1.79 * 10^-22 grams
The correct answer of the given question above would be a PICTOGRAM. OSHA’s required pictograms must be in the shape of a square set at a point and
include a black hazard symbol on a white background with a red frame sufficiently wide enough to
be clearly visible.
