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4 years ago

In stars mor massive than the sun, fusion continues until the core is almost all....

1 answer:

3 0

In stars more massive than the sun, the core temperature is hotter, which allows for fusion of more complex elements.

Most of the fusion occurs in the core.

In stars more massive than the sun, fusion continues through Deuterium, Carbon, and finally reaching iron/nickel.

Up to this point, the fusion reaction was endothermic, which means that the energy expended to produce the fusion reaction was exceeded by the energy produced in the reaction.

Fusion past iron is exothermic, and therefore the star will be able to survive by fusing elements heavier than iron.

After the core is almost entirely iron, the star is no longer in the Main Sequence.

So, fusion in stars more massive than the sun continue fusing until the core is almost entirely <em>iron</em>.

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One of the first recorded uses of forensic entomology being used in a criminal case happened in what time period?

ra1l [238]

The concept of forensic entomology dates back to at least the 13th century. However, only in the last 30 years has forensic entomology been systematically explored as a feasible source for evidence in criminal investigations

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3 years ago

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Which of the following is not a possible environmental effect of acid rain?

grin007 [14]

Answer:

but where are the options?

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2 years ago

A ball is tossed with enough speed straight up so that it is in the air several seconds. (a) What is the velocity of the ball wh

irina1246 [14]

(a) Zero

When the ball reaches its highest point, the direction of motion of the ball reverses (from upward to downward). This means that the velocity is changing sign: this also means that at that moment, the velocity must be zero.

This can be also understood in terms of conservation of energy: when the ball is tossed up, initially it has kinetic energy

$K=\frac{1}{2}mv^2$

where m is the ball's mass and v is the initial speed. As it goes up, this kinetic energy is converted into potential energy, and when the ball reaches the highest point, all the kinetic energy has been converted into potential energy:

$U=mgh$

where g is the gravitational acceleration and h is the height of the ball at highest point. At that point, therefore, the potential energy is maximum, while the kinetic energy is zero, and so the velocity is also zero.

(b) 9.8 m/s upward

We can find the velocity of the ball 1 s before reaching its highest point by using the equation:

$a=\frac{v-u}{t}$

where

a = g = -9.8 m/s^2 is the acceleration due to gravity, which is negative since it points downward

v = 0 is the final velocity (at the highest point)

u is the initial velocity

t = 1 s is the time interval

Solving for u, we find

$u=v-at = 0 -(-9.8 m/s^2)(1 s)= +9.8 m/s$

and the positive sign means it points upward.

(c) -9.8 m/s

The change in velocity during the 1-s interval is given by

$\Delta v = v -u$

where

v = 0 is the final velocity (at the highest point)

u = 9.8 m/s is the initial velocity

Substituting, we find

$\Delta v = 0 - (+9.8 m/s)=-9.8 m/s$

(d) 9.8 m/s downward

We can find the velocity of the ball 1 s after reaching its highest point by using again the equation:

$a=\frac{v-u}{t}$

where this time we have

a = g = -9.8 m/s^2 is the acceleration due to gravity, still negative

v is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

t = 1 s is the time interval

Solving for v, we find

$v = u+at = 0 +(-9.8 m/s^2)(1 s)= -9.8 m/s$

and the negative sign means it points downward.

(e) -9.8 m/s

The change in velocity during the 1-s interval is given by

$\Delta v = v -u$

where here we have

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

Substituting, we find

$\Delta v = -9.8 m/s - 0=-9.8 m/s$

(f) -19.6 m/s

The change in velocity during the overall 2-s interval is given by

$\Delta v = v -u$

where in this case we have:

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = +9.8 m/s is the initial velocity (1 s before reaching the highest point)

Substituting, we find

$\Delta v = -9.8 m/s - (+9.8 m/s)=-19.6 m/s$

(g) -9.8 m/s^2

There is always one force acting on the ball during the motion: the force of gravity, which is given by

$F=mg$

where

m is the mass of the ball

g = -9.8 m/s^2 is the acceleration due to gravity

According to Newton's second law, the resultant of the forces acting on the body is equal to the product of mass and acceleration (a), so

$mg = ma$

which means that the acceleration is

$a= g = -9.8 m/s^2$

and the negative sign means it points downward.

7 0

3 years ago

A train starts from rest and accelerates uniformly until it has traveled 2.1 km and acquired a forward velocity of The train the

Andreas93 [3]

Answer:

4.4 km

Explanation:

t = Time taken

u = Initial velocity = 24 m/s (Assumed)

v = Final velocity

s = Displacement

a = Acceleration = -0.065 m/s² (Assumed)

Distance = Speed × Time

$\text{Distance}=24\times 400=9600\ m$

The train travels for 9600 m.

$v=u+at\\\Rightarrow 0=24-0.065t\\\Rightarrow t=\frac{-24}{-0.065}=369.23\ s$

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=24\times 369.23+\frac{1}{2}\times -0.065\times 369.23^2\\\Rightarrow s=4430.76\ m$

The Distance the train traveled when it slowed down is 4.4 km

3 0

4 years ago

Speed deamplifier. Block 1 of mass m1 slides along an x axis on a frictionless floor at speed 4.00 m/s. Then it undergoes a oned

alisha [4.7K]

Answer:

29J

Explanation:

Please see attachment .

7 0

4 years ago