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yulyashka [42]
3 years ago
6

What is a change that will not affect the pressure in a container

Physics
2 answers:
Dimas [21]3 years ago
7 0

Answer:

changing the material that the fluids container is made of.

Lubov Fominskaja [6]3 years ago
7 0

<u>A change that will not affect the pressure in a container:</u>

The factors that affect the pressure inside a container are PVT (Pressure, Volume and Temperature). Apart from these three factors, changing or tweaking any other factor like, changing the material using which the container was made, etc would not affect the pressure.

In this case of a container, a change in pressure(adding or removing air from the container), volume (changing the amount of fluid present in the container), temperature (changing the temperature in which the container is kept) would all affect the pressure inside the container while something like, changing the material using which the container was made, would not change the pressure.

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light waves with a frequency of 7.26 x 10^14 HZ lies in the violet region of the visible spectrum. what is the wavelength of thi
pogonyaev

Answer:

4.13×10⁻⁷ m

Explanation:

Applying

v = λf................... Equation 1

Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.

make λ the subject of the equation

λ = v/f....................... Equation 2

Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.

From the question,

Given: f = 7.26×10¹⁴ Hz

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = (3×10⁸)/(7.26×10¹⁴)

λ = 4.13×10⁻⁷ m

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A 2.50 kg ball is attached to a 3.00 m bar and swung in a vertical circle. If the ball does not leave the circular loop, what mi
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Answer:

5.42 m/s

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what is the final volume of a gas with an initial volume of 200 .0ml if the pressure decreases from 500.0 kpa to 250.0 kpa
Serjik [45]

<u>Answer:</u>

Given Data:

V2 ?

V1 = 200 ml,

P1 = 500kpa and P2 = 2500kpa


From <em>Boyels law</em> (Ideal gas law) Where temperature remains constant, <em>Pressure is inversely proportional to volume.</em>

                   P1 .V1 = P2 . V2  ;       T=Constant

                        V2 = (P1.V1) ÷ P2

                              = (500×200) ÷(250)

                              = 400 ml

<em>The final volume of the gas is 400 ml.</em>

<em>Note: Increased pressure decreases the volume or decreased pressure increase the volume as they are inversely proportional.</em><em> Here in our answer pressure decreases from 500 kpa to 250 kpa so volume increases from 200 ml to 400 ml. </em>

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