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4 years ago

What is a change that will not affect the pressure in a container

Physics

2 answers:

Dimas [21]4 years ago

7 0

Answer:

changing the material that the fluids container is made of.

Lubov Fominskaja [6]4 years ago

7 0

<u>A change that will not affect the pressure in a container:</u>

The factors that affect the pressure inside a container are PVT (Pressure, Volume and Temperature). Apart from these three factors, changing or tweaking any other factor like, changing the material using which the container was made, etc would not affect the pressure.

In this case of a container, a change in pressure(adding or removing air from the container), volume (changing the amount of fluid present in the container), temperature (changing the temperature in which the container is kept) would all affect the pressure inside the container while something like, changing the material using which the container was made, would not change the pressure.

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Anarel [89]

Answer:

The impact force is 98000 N.

Explanation:

mass = 10 tons

The impact force is the weight of the object.

Weight =mass x gravity

W = 10 x 1000 x 9.8

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3 years ago

Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley

kenny6666 [7]

Answer:

Hello your question is incomplete attached below is the complete question

Answer : x ( acceleration of mass 4m ) = $\frac{g}{7}$

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Explanation:

Given data:

mass suspended = 4 meters

mass suspended at other end = 3 meters

first we have to express the kinetic and potential energy equations

The general kinetic energy of the system can be written as

T = $\frac{4m}{2} x^2 + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2$

T = $4mx^2 + 2my^2 -2mxy$

also the general potential energy can be expressed as

U = $-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant$

The Lagrangian of the problem can now be setup as

$L =4mx^2 +2my^2 -2mxy +2mgy + constant$

next we will take the Euler-Lagrange equation for the generalized equations :

Euler-Lagrange equation = $4x-y =0\\-2y+x +g = 0$

solving the equations simultaneously

x ( acceleration of mass 4m ) = $\frac{g}{7}$

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3 years ago

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Arte-miy333 [17]

Answer:

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Explanation:

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3 years ago

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3 years ago

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