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Liono4ka [1.6K]
1 year ago
7

a paper airplane gliding down towards the ground will experience the force of air resistance pushing up. the weight of the paper

airplane is 16 N down and the force of air resistance is 9 N up. find the net force
Physics
1 answer:
Oduvanchick [21]1 year ago
3 0

The net force acting on the airplane is 25N.

Forces acting on the paper airplane when it is in the air:

  • The forward force generated by the engine, propeller, or rotor is called thrust. It resists or defeats the drag force. It operates generally perpendicular to the longitudinal axis. However, as will be discussed later, this is not always the case.
  • Drag is an airflow disruption generated by the wing, rotor, fuselage, and other projecting surfaces that causes a backward, decelerating force. Drag acts backward and perpendicular to the relative wind, opposing thrust.
  • Weight is the total load carried by airplane, including the weight of the crew, fuel, and any cargo or baggage. Due to the influence of gravity, weight pulls the airplane downward.
  • Lift—acts perpendicular to the flight path through the center of lift and opposes the weight's downward force. It is produced by the air's dynamic influence on the airfoil.

Given.

Weight of the paper airplane, F1 = 16N

The force of air resistance, F2 = 9N

Net force = F1 + F2

Net force = 25N

Thus, the net force acting on the airplane is 25N.

Learn more about the net force here:

brainly.com/question/18109210

#SPJ1

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Answer:

54 × 5/18 = 15m/s

Explanation:

to convert km/hr to m/s you multiply by 5/18

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Can you help me with my homework please ? Science
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3 years ago
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6 0
2 years ago
Skater 1 has a mass of 105.0 kg and a velocity of 2.0 m/s to the left. He
mart [117]

The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

<h3>What is velocity?</h3>

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

  • mu+MU = mv+MV............ Equation 1

Where:

  • m = mass of the first skater
  • M = mass of the second skater
  • u = initial velocity of the first skater
  • U = initial velocity of the second skater
  • v = final velocity of the first skater
  • V = final velocity of the second skater.

make v the subject of the equation.

  • v = (mu+MU-MV)/m................ Equation 2

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

  • m = 105 kg
  • u = -2 m/s
  • M = 71 kg
  • U = 5 m/s
  • V = -3.4 m/s.

Substitute these values into equation 2

  • v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
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  • v = 3.68 m/s
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Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Learn more about velocity here: brainly.com/question/25749514

7 0
2 years ago
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Hope this helped.
4 0
3 years ago
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