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3 years ago

Technology used during a scientific experiment to gather data

Chemistry

1 answer:

ddd [48]3 years ago

3 0

Hi!

The answer to this is true.

Hope it helps! :)

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Iron and carbon monoxide are made by heating 5.53 kg of iron ore, Fe₂O₃, and carbon. What is the theoretical yield of iron in ki

vfiekz [6]

Answer:

Mass of Fe produced = 3.86785211069 ≈ 3.87 kg

Explanation:

From the question the chemical reaction can be written as follow :

Fe2O3 + C → Fe + CO

Balance the equation

Fe2O3 + 3C → 2Fe + 3CO

compute the molecular mass of Fe2O3 and atomic mass of Iron(Fe)

Molecular mass of Fe2O3 = 55.845(2) + 15.999(3) = 111.69 + 47.997 = 159.687 g

Atomic mass of iron = 55.845 g

From the balanced equation

159.687 g of Fe2O3 produces 2 × 55.845 = 111.69 g of Fe(iron)

Convert the 5.53 kg to gram

1 kg = 1000 g

5.53 kg = 5.53 × 1000 = 5530 g

since,

159.687 g of Fe2O3 produces 2 × 55.845 = 111.69 g of Iron(Fe)

5530 g of Fe2O3 will produce

cross multiply

Mass of Fe produced =5530 × 111.69/159.687

Mass of Fe produced = 617645.7

/159.687

Mass of Fe produced = 3867.85211069 g

convert to kg

1000 g = 1 kg

3867.85211069 = 3867.85211069/1000

Mass of Fe produced = 3.86785211069 ≈ 3.87 kg

3 0

3 years ago

Ecology is defunded as the environment study of

stiks02 [169]

Answer:

sicoligy

Explanation:

7 0

3 years ago

Read 2 more answers

LAB: predicting products

kondor19780726 [428]

Answer:

1) synthesis MgI2

2) double replacement CuS + (HCl)2

3) double replacement, not sure ab the formula sorry

4 0

2 years ago

The three major types of faults are normal, reverse and syncline. true or false

Novosadov [1.4K]

The three major types of faults are Normal, Reverse and Strike-slip faults.

Answer: FALSE

6 0

3 years ago

Read 2 more answers

Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of

jeka57 [31]

Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x

Total energy required = $2260x+x\times2.010\times(135-100)=2260x+70.35x=2330.35x$

$2330.35x=1048815\\x=450.068g$

Hence, there was 450.068g of water in the pot.

8 0

2 years ago