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Len [333]
3 years ago
6

Which method is used to obtain petrol from petroleum?

Chemistry
2 answers:
kotykmax [81]3 years ago
6 0

Explanation:

fractional distillation method is used to obtain petrol from petroleum...

hope it helps

tamaranim1 [39]3 years ago
5 0

Answer:

D fractional distillation

Explanation:

answer from gauth math

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whAt is an example of a chemical change is: Boiling water, Melting butter, Spreading cream cheese, Toasting bread?
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Answer:

Toasting Bread

Explanation:

Toasting bread cannot be transformed

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How many electrons are transferred during the formation of one molecule of al2o3?
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Answer:
            Six electrons are transferred in the formation of Al₂O₃.

Explanation:
                   Aluminium metal and Oxygen react to form Al₂O₃ as,

                                2 Al  +  3/2 O₂    →    Al₂O₃

Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms. 

So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.
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Which is classified as an inner transition element
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They include elements 57-71 (lanthanides) and 89-103 (actinides)
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A popular kitchen appliance
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CH3 + HCl <=> CH3Cl + H2O
dmitriy555 [2]

Answer:

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Explanation:

Step 1: Data given

Kp = 4.7 x 10^3 at 400K

Pressure of CH3OH = 0.250 atm

Pressure of HCl = 0.600 atm

Volume = 10.00 L

Step 2: The balanced equation

CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)

Step 3: The initial pressure

p(CH3OH) = 0.250atm

p(HCl) = 0.600 atm

p(CH3Cl)= 0 atm

p(H2O) = 0 atm

Step 3: Calculate the pressure at the equilibrium

p(CH3OH) = 0.250 - X atm

p(HCl) = 0.600 - X atm

p(CH3Cl)= X atm

p(H2O) = X atm

Step 4: Calculate Kp

Kp = (pHO * pCH3Cl) / (pCH3* pHCl)

4.7 * 10³ =  X² /(0.250-X)(0.600-X)

X = 0.249962

p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm

p(HCl) = 0.600 - 0.249962 = 0.350038 atm

p(CH3Cl)= 0.249962 atm

p(H2O) = 0.249962 atm

Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)

Kp = 4.7 *10³

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

4 0
3 years ago
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