All categories

2 years ago

PLEASE HELP ME WITH THID IFK IT!! ILL GIVE YOU EXTRA POINTS

Chemistry

1 answer:

xenn [34]2 years ago

8 0

But a check at the bottom and x at the top

You might be interested in

defon

Answer:

0.0357

mol

CaCl

is dissolved in water to make a

0.420

solution, what is the volume of the solution?

4 0

2 years ago

Aspirin tablets contain the active ingredient (aspirin) and various inactive ingredients. Suggest what types of inactive ingredi

Debora [2.8K]

Binders ; fillers. They are inert substances to hold pill shape and preserve the medication, its ph / etc.

5 0

3 years ago

A chemistry student needs 60.0 g of 2-ethyltoluene for an experiment. He has available 1.5 kg of a 15.3% w/w solution of 2 ethyl

Mila [183]

Answer:

392 g

Explanation:

The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.

With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:

Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene

Mass of solution = 392 g

8 0

2 years ago

Lithium bromide dissociates in water according to the following thermochemical equation: LiBr(s) → Li+ (aq) + Br– (aq) ΔH = –48.

madreJ [45]

Answer:

Final temperature of water is $48.3^{0}\textrm{C}$

Explanation:

1 mol of LiBr releases 48.83 kJ of heat upon dissolution in water.

So, 2 moles of LiBr release $(2\times 48.83)kJ$ or 97.66 kJ of heat upon dissolution in water.

This amount of heat is consumed by 1000.0 g of water. Hence temperature of water will increase.

Let's say final temperature of water is $t^{0}\textrm{C}$ .

So, change in temperature ( $\Delta T$ ) of water is $(t-25)^{0}\textrm{C}$ or (t-25) K

Heat capacity (C) of water is $4.184\frac{J}{g.K}$

Hence, $m_{water}\times C_{water}\times \Delta T_{water}=97.66\times 10^{3}J$

where m is mass

So, $(1000.0g)\times (4.184\frac{J}{g.K})\times (t-25)K=97.66\times 10^{3}J$

or, $t=48.3$

Hence final temperature of water is $48.3^{0}\textrm{C}$

3 0

3 years ago

Suppose you used excess sulfuric acid in all the flasks. How many moles of CO2would be released in flask 7? The molar mass of so

taurus [48]

Answer:

Number of produced moles of carbondioxide is 0.113 mol.

Explanation:

Excess of sulphuric acid is present.And the sodium carbonate is completely consumed.

Molar mass of sodium carbonate = 105.99g/mol

Given mass of sodium carbonate =12 g/mol

$Number\,of\,moles=\frac{Given\,mass}{Molar\,mass}$

$Number\,of\,moles=\frac{12}{105.99}=0.113mol$

one mole of sodium carbonate produce one mole of carbondioxide.

0.113 mole of sodium carbonate produce 0.113 mole of carbondioxide.

$Mass\,of\,CO_{2}produced=Moles\times Molar\,mass$

$=0.113\times 44g/mol=4.98g$

Therefore, 0.113 mol of carbondioxide produced in flask 7.

6 0

3 years ago