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Lemur [1.5K]
2 years ago
9

Write a point-slope equation for the line that has slope 1.4 and passes through the point (21, 5). Do not use parenthesis on the

y side.
Mathematics
1 answer:
kicyunya [14]2 years ago
4 0
We know that
the equation of a line is
(y-y1)=m*(x-x1)
slope m=1.4
point <span>(21, 5)
</span>(y-y1)=m*(x-x1)----> y-5=1.4*(x-21)

the answer is
y-5=1.4*(x-21)

You might be interested in
g Make a decision about the given claim. Use only the rare event​ rule, and make subjective estimates to determine whether event
vagabundo [1.1K]

Answer:

There is not sufficient evidence to support the claim.

Step-by-step explanation:

The claim to be tested is:

The mean respiration rate (in breaths per minute) of students in a large statistics class is less than 32.

To test this claim the hypothesis can be defined as follows:

<em>H₀</em>: The mean respiration rate of students is 32, i.e. <em>μ</em> = 32.

<em>Hₐ</em>: The mean respiration rate of students is less than 32, i.e. <em>μ</em> < 32.

The sample mean  respiration rate of students is 31.3.

According to the claim the sample mean is less than 32.

The sample mean value is not unusual if the claim is true, and the sample mean value is also not unusual if the claim is false.

Thus, there is not sufficient evidence to support the claim.

7 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
2 years ago
Tan30°+cos30°÷tan30°×cos30°​
jonny [76]

Answer:

{1/√3+1/2} ÷{1/√3× 1/2}

  • (2+√3)/2√3÷(1/2√3)
  • 2+√3+1 /2√3
  • (2+1 )+√3 /2√3
  • 3 +√3 /2√3
4 0
3 years ago
How do you simplify -2x(x+3)-(x+1)(x-2)
Elena L [17]
1. Distribute the -2x with the (x+3)
2.Multiply (x+1) and (x-2) which is (x2- x -2)
So far it should look like (-2x^2 -6x) - (x^2-x-2)
3. Distribute out the negative
Should look like this -2x^2 -6x - x^2+x+2
4. Lastly combine like terms

Your result should be:
-3x^2 - 5x + 2

Hope this helps!
8 0
2 years ago
Read 2 more answers
Question 1 of 10 Jerry drew AJKL and AMNP so that K = ZN, ZLE ZP, JK = 6, and MN = 18. Are AJKL and AMNP similar? If so, identif
butalik [34]

Answer:

This is the answer I got

Step-by-step explanation:

JK / KL = MN / NP 6 / 4 = 18 / 12

Now u cross multiply. if both numbers are equal, they are similar. In this case, they are similar. 6 x 12 = 4 x 18

72 = 72

though the two corresponding sides of the triangles mentioned are proportional (proportionality being 1:3 ) but they need not be similar

for similarity either the third corresponding sides must be proportional or the included angle between the two proportional sides must be equal

5 0
3 years ago
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