Answer:
If a chord had notes with frequencies of 100, 1,000, and 6,000 Hz, the basilar membran would vibrate at multiple positions, with peaks at A, B, and C.
Explanation:
Answer:
Acceleration of the car will be equal to
Explanation:
As the car is initially stop so initial velocity of the car u = 0 m /sec
It is given that after moving a distance of 101 m velocity of car is 19.1 m/sec
So final velocity of the car v=19.1 m/sec
We have to find the acceleration of the car
From third equation of motion we know that
So
So acceleration of the car will be equal to
41.2 = h-1/2g(t-1)^2
<span> {-h = -1/2gt^2-1/2g+g*t-41.2
</span><span> {h = 1/2gt^2
</span><span> summing them up
</span><span> 0 = -1/2g+g*t-41.2
</span><span> 41.2 +4.9 = g*t
</span><span> t = 46.1/9.8 = 4.70 sec
</span><span> h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m </span>
Answer:
the speed of the boat is 21.22ft/min
Explanation:
Hello!
To solve this exercise follow the steps below.
1. Draw the complete scheme of the problem (see attached image).
2. As you can see in the image, our goal is to determine the horizontal component of the velocity (Vx) that corresponds to that of the boat, for this the first thing we do is find the alpha angle using the height and the hypotenuse of the triangle.
3. Finally we find the horizontal velocity component using the cosine function
the speed of the boat is 21.22ft/min