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Juliette [100K]
3 years ago
6

You want to launch a stone using the elastic band of a slingshot. The force that the elastic band applies to an object is given

by F = −α∆s4 , where α = 45 N m4 and ∆s is the displacement of the elastic band from its equilibrium position. You load the slingshot with the stone and pull back on the stone horizontally, stretching the the elastic band 20 cm. How much work do you do on the stone-elastic band system?
Physics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

0.00288 J

Explanation:

We know that

W= Fds

F = −α∆s^4

α = 45 N/m^4 and ∆s = displacement

W= −α∆s^4ds

integrating both the sides from s= 0 to 0.2

W= 45/5×0.2^5= 0.00288 J

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What technique is used by scientists to determine which of several explanations is the best explanation
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Answer:

When conducting research, scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a hypothesis (often in the form of an if/then statement), the results aiming to support or contradict a theory.

I HOPE ITS RIGHT

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3 years ago
Which statement about atmospheric pressure near Earth’s surface is true
notka56 [123]
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3 years ago
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When the Glen Canyon hydroelectric power plant in Arizona is running at capacity, 690 m3 of water flows through the dam each sec
igomit [66]

Answer:

The maximum electric power output is P_{max} =1.339*10^{9} \ W

Explanation:

From the question we are told that

        The capacity of the hydroelectric plant is \frac{V}{t}   =  690 \ m^3 /s

         The level at which water is been released is h  =  220 \ m

        The efficiency is  \eta  =0.90

       

The electric power output is mathematically represented as

       P  = \frac{PE_l - PE _o}{t}

Where  PE_l is the potential energy at  level h which is mathematically evaluated as  

          PE_l  =  mgh

and  PE_o  is  the potential energy at ground level which is mathematically evaluated as  

          PE_o  =  mg(0)

         PE_o  =  0

So  

         P  = \frac{mgh}{t}

here  m  =   V *  \rho

where V is volume  and  \rho is density of water whose value is  \rho = 1000 kg/m^3

 So  

         P  = \frac{(\rho * V) * gh}{t}

        P  = \frac{V}{t} * gh \rho

substituting values  

       P  =690 * 9.8 * 220 * 1000

      P  =1.488*10^{9} \ W

The maximum possible electric power output is

           P_{max} = P * \eta

substituting values  

         P_{max} =1.488*10^{9} * 0.90

         P_{max} =1.339*10^{9} \ W

6 0
3 years ago
In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward
BaLLatris [955]

Answer:

= 4.3 × 10 ⁻¹⁴ m

Explanation:

The alpha particle will be deflected when its kinetic energy is equal to the potential energy

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Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C

Kinetic energy of  the alpha particle = 5.28 × 10⁶ × 1.602 × 10⁻¹⁹ J ( 1 eV)

=  8.459 × 10⁻¹³

k electrostatic force constant = 9 × 10⁹ N.m²/c²

Kinetic energy = potential energy =   k q₁q₂ / r where r is the closest distance the alpha particle got to the gold nucleus

r = (  9 × 10⁹ N.m²/c² × 3.2 × 10⁻¹⁹ C × 1.264 × 10⁻¹⁷C) / 8.459 × 10⁻¹³

= 4.3 × 10 ⁻¹⁴ m

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-- Slowing down . . .

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-- Turning away from a straight line . . .
   
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              the door, or whatever or whomever you're leaning against

6 0
3 years ago
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