Answer:
94.4g/mol is molar mass of the unknown
Explanation:
Based on the freezing point depression equation:
ΔT = Kf*m*i
<em>Where ΔT is the depression in freezing point (1.87°C)</em>
<em>Kf is freezing point depression constant of water (1.86°Ckg/mol)</em>
<em>And i is Van't Hoff factor (1 for nonelectrolyte solutes)</em>
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Replacing:
1.87°C = 1.86°CKg/mol*m*i
1.005mol/kg solvent = m
Using the mass of the solvent we can find the oles of the nonelectrolyte:
1.005mol/kg solvent * 0.4764kg = 0.479moles
Molar mass is defined as the ratio between mass of a substance in grams and moles, that is:
45.2g / 0.479mol =
<h3>94.4g/mol is molar mass of the unknown</h3>
Answer:
Exocytosis
Explanation:
Some molecules are simply too big to move via a transport protein or the plasma membrane. To carry these macromolecules in or out of the cell, cells employ two more active transport pathways. Macromolecules or big particles are transported across the plasma membrane via Vesicles transport or other cytoplasmic structures. They are of two types, Endocytosis and Exocytosis
From the given information, Exocytosis is the right answer.
It is the process of vesicles combining with the plasma membrane thereby releasing their contents to the exterior of the cell. When a cell creates components for export, such as proteins, or when it gets rid of a waste product or a toxin, exocytosis occurs. Exocytosis is the process by which newly generated membrane proteins and membrane lipids are transported on top of the plasma membrane.
Answer:
13.6233
Explanation:
calculate the joules by dividing the energy value by 4.184
