Find the domain of this equation {-2

Consider triangle PQR. What is the length of side QR?

Inessa [10]

Answer:

Its 16 units!

Step-by-step explanation:

I did thee test on edge :)

6 0

3 years ago

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Derek owns a landscape business. He charges a fixed fee of $30 plus $1 per 1,000 square feet of lawn mowed. Derek's earnings (in

fgiga [73]

Let f(x) represents function that tells us Derek's earning depending on square feet of lawn mowed which is x.

First we construct function:

f(x) = x/1000 * 1 + 30

x/1000 is a number that tells us the number of mowed units. for x = 1000 square feet he earns 1 dollar that is why we have to divide x by 1000.

if he earned 204 first week that means that x =:
204 = x/1000 + 30
x/1000 = 174
x = 174 000
if we check for each week that he worked we will see that square footage of the lawns he mowed match forth (last) option.

Answer is D.

8 0

3 years ago

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How many blocks will give us our total, 30% of $500

Gennadij [26K]

Answer:

150

Step-by-step explanation:

30% of 500 is 150 :/

6 0

3 years ago

Help me out with these please!

garik1379 [7]

Step-by-step explanation:

1. a) q=4+0.8(7)

q=4+5.6

q=9.6

b) q=4+0.8(100)

q=4+80

q= 84

2. a) 12=4+0.8p

-4 -4

8=0.8p

0.8 0.8

10=p

b) 60=4+0.8p

-4 -4

56=0.8p

0.8 0.8

70=p

8 0

3 years ago

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The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

3 years ago