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3 years ago

15

If you received a score of 80% on an assignment,what is the ratio of correct answers to incorrect answers

1 answer:

Cerrena [4.2K]3 years ago

6 0

Im not really sure so ill just give it a try.
mayeb 70? ten less"

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What is the missing reason in step 5

Lady_Fox [76]

The Correct Answer On Edgen Is

<u>A) Linear pair postulate.</u>

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3 years ago

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A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 46.046.0 and

Gala2k [10]

Answer:

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is 0.10

Step-by-step explanation:

The Uniform Distribution, also known as Rectangular Distribution, is a type of Continuous Probability Distribution. It has a continuous random variable restricted to a finite interval and its probability function has a constant density during this interval.

The formula of probability if given by:

f(x)=

$\left \{ {{\frac{1}{b-a}; \ a \leq x \leq b } \atop {0}; \ x \ otherwise } \right.$

In this exercise a= 46.0 and b= 56.0

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is:

$\int\limits^{51.25}_{50.25} {\frac{1}{56-46} } \, dx = \int\limits^{51.25}_{50.25} {\frac{1}{10} } \, dx = \frac{1}{10} \times (51.25 - 50.25)=\frac{1}{10}=0.1$

7 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

The ratio of Ds to As in the school was 4 to 72. If there were 1080 As in the school this term, how many Ds were there?

Vika [28.1K]

Answer:

60

Step-by-step explanation:

1080/72 *15 = number if Ds

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3 years ago

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1) 1, 4, 16, 64, ...<br>CR=L<br>Next 3 Terms:

avanturin [10]

Answer:

256, 1024, 4096.

Step-by-step explanation:

The rule is x*4.

--> 1*4 = 4.

--> 4*4 = 16.

--> 16*4 = 64.

--> 64*4 = 256.

--> 256*4 = 1024.

--> 1024*4 = 4096.

4 0

3 years ago

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