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3 years ago

13

a constant force acts on an object of mass 10 kg for a duration of 2 seconds it increases the object velocity from 4metre per se

c to 8 metre per second find the magnitude of the applied force

1 answer:

inn [45]3 years ago

3 0

Answer:

F=ma

a=v/t

a=vf-vi/t

a=8-4/2

a=4÷2

a=2msec*2

F=10×2

F=20N

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