Question

a constant force acts on an object of mass 10 kg for a duration of 2 seconds it increases the object velocity from 4metre per sec to 8 metre per second find the magnitude of the applied force​

Answer 1

Answer:

F=ma

a=v/t

a=vf-vi/t

a=8-4/2

a=4÷2

a=2msec*2

F=10×2

F=20N