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eduard
3 years ago
10

Elias observed a sample in the classroom. The sample was a liquid at room temperature. He performed a conductivity test and foun

d that it did not conduct electricity. Which classification would best fit the sample?
A) ionic
B) metal
C) nonmetal
D) salt
Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:

B

Explanation:

Nonmetals are poor conduster to heat and electricity

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What role does team collaboration play in successfully planning a mission to Mars?
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Answer:it helps get everyone in the same page

Explanation:

This is important so everyone knows what they should be doing

4 0
3 years ago
The answer please? I have exam tomo
makkiz [27]

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Explanation:

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5 0
3 years ago
What is the centripetal force that would be required to keep a 4.0 kg mass moving in a horizontal circle with a radius of 0.80 m
KIM [24]

Answer:

D. 1.8 × 102 newtons radially inward

Explanation:

The magnitude of the centripetal force is given by:

F=m\frac{v^2}{r}

where

m is the mass of the object

v is the tangential speed

r is the radius of the circular trajector

In this problem, we have m = 4.0 kg, v = 6.0 m/s and r = 0.80 m, therefore substituting into the equation we get

F=(4.0 kg)\frac{(6.0 m/s)^2}{0.80 m}=180 N

The centripetal force is the force that keeps the object in a circular trajectory, so it is a force that is always directed inward (towards the centre of the circular path) and radially. Therefore, the correct answer is

D. 1.8 × 102 newtons radially inward

4 0
4 years ago
Read 2 more answers
Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. What is the truck’s velocity?
gladu [14]

<u>Answer:</u>

The velocity of the truck is 34 m/s.

<u>Explanation:</u>

The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:

<em>p = mv</em>

Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.

So substituting the given values in the above formula to find the velocity of the truck.

Truck's velocity = \frac{40120}{1180} = 34 m/s.

3 0
3 years ago
I need help answering this question.
Sloan [31]
The work done is the loss of kinetic energy.

Loss of kinetic energy = m*(v1^2 - v2^2)/2 = 10 kg * [ (99m/s)^2 - (1m/s)^2]/2 = 49,000 J

 
6 0
3 years ago
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