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Oxana [17]
3 years ago
8

The volume of a container is 40 cm 3 . It has a length of 4 cm, a width of 2 cm. What is the height of the container?

Physics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

5cm

4x2 =8, 8x5 =40

so 4 x 2 x 5 = 40cm3

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A uniform continuous line charge with net positive charge Q and length L lies on the x-axis from −L2 to +L2. This problem asks a
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Answer:

(C) zero (there is no net horizontal component of the E-field)

Explanation:

If we subdivide the bar into small pieces, each piece (dx) contains a charge (dq), the electric field of each piece is equivalent to the field of a punctual electric charge, and has a direction as shown in the attached figure. For each piece (dx) in the negative axis there is another symmetric piece (dx) in the positive axis, and as we see in the figure for symmetry the sum of their electric fields gives a resultant in the Y axis (because its components in X are cancelled by symmetry).

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What average energy of particles does temperature measures?​
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When you lift an object, you add the energy of lifting to the object.<br> Tor F
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6 0
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A block with mass m is pulled horizontally with a force F_pull leading to an acceleration a along a rough, flat surface.
Simora [160]

Answer:

\mu_k=\frac{a}{g}

Explanation:

The force of kinetic friction on the block is defined as:

F_k=\mu_kN

Where \mu_k is the coefficient of kinetic friction between the block and the surface and N is the normal force, which is always perpendicular to the surface that the object contacts. So, according to the free body diagram of the block, we have:

N=mg\\F_k=F=ma

Replacing this in the first equation and solving for \mu_k:

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6 0
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An object of mass 20g taken at a height of 2m above the ground. Which type of energy is possessed by the object at this height ?
In-s [12.5K]
<h3><u>Given</u> </h3>
  • Mass of an object is \bf\red{20 g}
  • Height of the body is \bf\green{2 m}
<h3><u>To Find</u></h3>
  • Value of the energy

<h3><u>Solution</u></h3>

{\purple {\underline{\boxed{\sf{ Potential\: Energy \:=\: mgh}}}}}

Where,

  • \sf\red{m} = Mass
  • \sf\green{g} = Gravity
  • \sf\blue{h} = Height

Now, Converting gram to kg

\longrightarrow\: 1000g = 1kg

\longrightarrow\: 20g = \sf\dfrac{20}{1000}

\longrightarrow\: = 0.02 kg

According to the question

\sf\red{Mass \:= \:0.02 kg}

\sf\green{Gravitational \;force \:= \;10 m/s^{2}}

\sf\purple{Height\: =\: 2 m}

Putting these values

\to\: Potential Energy = mgh

\to\: Potential Energy = 0.02 × 10 × 2

\to\: Potential Energy = 0.2 × 2

\to\: Potential Energy = \bf\pink{0.4\:joules}

7 0
3 years ago
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