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Minchanka [31]
2 years ago
14

What is the correct answer?

Physics
1 answer:
LuckyWell [14K]2 years ago
7 0

Answer:

Option (4)

Explanation:

Given polynomial is,

P(x) = 1x³ - 7x² + 2x + 40

If (x - 5) is a factor of the given polynomial,

Synthetic division by x = 5,

5 |  1    -7     2     40

    <u> ↓    5   -10   -40</u>

     1    -2    -8      0

Therefore, factored form of the polynomial will be,

P(x) = (x - 5)(x²- 2x - 8)

Now we further factorize the expression (x² - 2x - 8),

(x² - 2x - 8) = x²- 4x + 2x - 8

                  = x(x - 4) + 2(x - 4)

                  = (x + 2)(x - 4)

Now fully factored form of the polynomial will be,

P(x) = (x - 5)(x + 2)(x - 4)

Therefore, remaining factors of the polynomial other than (x - 5) are (x - 4)(x + 2)

Option (4) will be the correct option.

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A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total
Lynna [10]

Explanation:

Given Data

Total mass=93.5 kg

Rock mass=0.310 kg

Initially wagon speed=0.540 m/s

rock speed=16.5 m/s

To Find

The speed of the wagon

Solution

As the wagon rolls, momentum is given as

P=mv

where

m is mass

v is speed

put the values

P=93.5kg × 0.540 m/s

P =50.49 kg×m/s

Now we have to find the momentum of rock

momentum of rock = mv

momentum of rock = (0.310kg)×(16.5 m/s)

momentum of rock =5.115 kg×m/s  

From the conservation of momentum we can find the wagons momentum So

wagon momentum=50.49 -5.115 = 45.375 kg×m/s  

Speed of wagon = wagon momentum/(total mass-rock mass)

Speed of wagon=45.375/(93.5-0.310)

Speed of wagon= 0.487 m/s

Throwing rock backward,

momentum of wagon = 50.49+5.115 = 55.605  kg×m/s

Speed of wagon = wagon momentum/(total mass-rock mass)

speed of wagon = 55.605  kg×m/s/(93.5kg-0.310kg)

speed of wagon= 0.5967 m/s

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