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ahrayia [7]
4 years ago
13

A combined circuit has two resistors in parallel (6.0 ohms and 8.0 ohms) and another in series (13.0 ohms). If the power source

is 9.0 volts, what will the current be?
A. 1.3 amps
B. 0.33 amps
C. 0.55 amps D.
2.6 amps
Physics
1 answer:
Blababa [14]4 years ago
5 0

Answer:

Option C: 0.55 Amps

Explanation:

First find the equivalent resistance for the given circuit:

The two resistors in parallel are equivalent to:

\frac{1}{Re} =\frac{1}{8} +\frac{1}{6} =\frac{14}{48} \\Re=\frac{48}{14} =3.428 ohms

Now we add this to the resistor that is in series (13 ohms) to find the total equivalent resistance for the circuit:

Re = 3.428 ohms + 13 ohms = 16.428 ohms

We use this result to find the current in the circuit by using Ohm's law:

V=R*I\\ I=\frac{V}{R} =\frac{9}{16.428} =0.5478 Amps

This can be rounded to 0.55 Amps

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An electron of kinetic energy 1.59 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 35.4 cm
Blizzard [7]

Answer:

a) v = 2.36 \cdot 10^{7} m/s

b) B = 3.80 \cdot 10^{-4} T

c) f = 1.06 \cdot 10^{7} Hz

d) T = 9.43 \cdot 10^{-8} s

Explanation:

a) We can find the electron's speed by knowing the kinetic energy:

K = \frac{1}{2}mv^{2}

Where:    

K: is the kinetic energy = 1.59 keV

m: is the electron's mass = 9.11x10⁻³¹ kg

v: is the speed =?

v = \sqrt{\frac{2K}{m}} = \sqrt{\frac{2*1.59 \cdot 10^{3} eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}}{9.11 \cdot 10^{-31} kg}} = 2.36 \cdot 10^{7} m/s

b) The electron's speed can be found by using Lorentz's equation:

F = q(v\times B) = qvBsin(\theta)   (1)

Where:

F: is the magnetic force

q: is the electron's charge = 1.6x10⁻¹⁹ C

θ: is the angle between the speed of the electron and the magnetic field = 90°

The magnetic force is also equal to:

F = ma_{c} = m\frac{v^{2}}{r}   (2)

By equating equation (2) with (1) and by solving for B, we have:

B = \frac{mv}{rq} = \frac{9.11 \cdot 10^{-31} kg*2.36 \cdot 10^{7} m/s}{0.354 m*1.6 \cdot 10^{-19} C} = 3.80 \cdot 10^{-4} T

c) The circling frequency is:

f = \frac{1}{T} = \frac{\omega}{2\pi} = \frac{v}{2\pi r}

Where:

T: is the period = 2π/ω

ω: is the angular speed = v/r

f = \frac{v}{2\pi r} = \frac{2.36 \cdot 10^{7} m/s}{2\pi*0.354 m} = 1.06 \cdot 10^{7} Hz

d) The period of the motion is:

T = \frac{1}{f} = \frac{1}{1.06 \cdot 10^{7} Hz} = 9.43 \cdot 10^{-8} s

I hope it helps you!

8 0
3 years ago
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ddd [48]
I believe the answer is the white dwarf.

The sun will cool then heat up again is my understanding. Hope this helps
3 0
3 years ago
For the chemical reaction C2H6 --> C2H4 + H2 + 137kJ, the chemical energy of the A. reactant and the chemical energy of the p
Goryan [66]

Answer: The chemical energy of reactants is greater than the chemical energy of products.

Explanation: In the given reaction

C_2H_6\rightarrow C_2H_4 + H_2 +137 kJ

It can be seen that the energy has been released. Thus we can say that reactants have converted to products by release of energy. Thus energy of products is less as compared to energy of reactants as some of the energy has been released.


4 0
3 years ago
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Answer:

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3 0
2 years ago
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an object is moving with a speed of 35 m/s and has a kinetic energy of 1500 J, what is the mass of the object?
Elena-2011 [213]
You'd use the equation kinetic energy=mass*0.5*speed^2
So you'd rearrange this to get mass =kinetic energy /0.5 *speed^2
Which is mass= 1500J/0.5*35^2
=2.44897959183673469........kg
5 0
3 years ago
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