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3 years ago

PLEASE HELPPPPP!!Calculate the net force acting on obiect A. In your answer, be sure to include the number, unit, and

Physics

1 answer:

asambeis [7]3 years ago

6 0

Answer:

4 N to the right

Explanation:

For the object in this problem, we have 2 forces acting on it:

- A force of 2 N, to the right

The two forces are in line: this means that the two vectors can be simply added by calculating their algebraic sum.

If we take right as positive direction, the two forces can be written as

F1 = +2 N

F2 = +2 N

So, the net force will be

$F=F_1+F_2=+2+2=+4 N$

And the positive sign means the direction is to the right.

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Which property of a substance is not altered by a physical change?

Bezzdna [24]

Composition Is the property

6 0

3 years ago

Read 2 more answers

A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl

Hunter-Best [27]

The ideal spring equation is

   Stretch = K times Force .

This says that the stretch is directly proportional to the force.
In simple English, that means that if you double the force, then
you double the stretch, and if you multiply the force by π or
any other number, you multiply the stretch by the same number.

So you can always write a proportion for a spring:

   Stretch₁ / Force₁ = Stretch₂ / Force₂ .

Part A:

In Part-A of this question, the force is increased to (2.5 / 2.0) = 1.25 times .

So the stretch is also increased to 1.25 times .

   (1.25) x (6.1 cm) = 7.625 cm .

6 0

4 years ago

La estrella mas proxima a la tierra esta a 2 años de luz. Calcula esta distancia en unidades del SI

tino4ka555 [31]

Answer:

$2\ ly=1.89\times 10^{16}\ m$

Explanation:

The question says that, "The closest star to the earth is 2 light years away. Calculate this distance in SI units".

Given that,

The distance between the closest star and the Earth is 2 light years.

The SI unit of distance is m. It means we need to convert light years to meters. We know that,

$1\ ly=9.461\times 10^{15}\ m$

2 light-years means,

$2\ ly=2\times 9.461\times 10^{15}\ m\\\\=1.89\times 10^{16}\ m$

So, the required distance is equal to $1.89\times 10^{16}\ m$ .

5 0

3 years ago

What is the force required to stop a 20 kg man traveling at 12.3 m/s East in 0.9 s? *Round to TWO decimal points and include you

abruzzese [7]

F = ma

We have mass = 20kg

And we need to solve for acceleration

So acceleration is change in velocity over time, in this case we have one velocity and we can assume the man started from rest so

12.3 / 0.9 = a

a = 13.6667

Now we can plug that into F = ma

F = (20)(13.6667)

F = 273.334

Rounding

F = 273.33

Now he is traveling east so we need a force towards the rest, or in the opposite direction to stop his motion.

If we assume east is the positive direction then we need a force of

-273.33 N to stop the man or 273.33 towards the west.

4 0

4 years ago

The frequency of a certain sound is 440 Mz. What is the wavelength of this sound when the temperature of the air is (a) 20°C; (b

Serggg [28]

Answer:

Explanation:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

Let's plug in our given values and see what we get!

340

440

−

0.773

3 0

2 years ago