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3 years ago

PLEASE HELPPPPP!!Calculate the net force acting on obiect A. In your answer, be sure to include the number, unit, and

Physics

1 answer:

asambeis [7]3 years ago

6 0

Answer:

4 N to the right

Explanation:

For the object in this problem, we have 2 forces acting on it:

- A force of 2 N, to the right

The two forces are in line: this means that the two vectors can be simply added by calculating their algebraic sum.

If we take right as positive direction, the two forces can be written as

F1 = +2 N

F2 = +2 N

So, the net force will be

$F=F_1+F_2=+2+2=+4 N$

And the positive sign means the direction is to the right.

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A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.

cupoosta [38]

Answer:

a) The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

Explanation:

a) The vectorial equation of momentum is represented by the following expression:

$\vec p = m\cdot \vec v$ (1)

Where:

$\vec p$ - Vector momentum, measured in kilogram-meters per second.

$m$ - Mass of the particle, measured in kilograms.

$\vec v$ - Vector velocity, measured in meters per second.

If we know that $m = 2.93\,kg$ and $\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]$ , then the momentum is:

$\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]$

$\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]$

The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of momentum are represented by the following expressions:

$\|\vec p \| = \sqrt{p_{x}^{2}+p_{y}^{2}}$ (2)

$\theta = \tan^{-1}\left(\frac{p_{y}}{p_{x}} \right)$ (3)

Where:

$\|\vec p\|$ - Magnitude of momentum, measured in kilogram-meters per second.

$\theta$ - Direction of momentum, measured in sexagesimal degrees.

If we know that $p_{x} = 8.731\,\frac{kg\cdot m}{s}$ and $p_{y} = -11.661\,\frac{kg\cdot m}{s}$ , then the magnitude and direction of momentum are, respectively:

$\|\vec p\| = \sqrt{\left(8.731\,\frac{kg\cdot m}{s} \right)^{2}+\left(-11.661\,\frac{kg\cdot m}{s} \right)^{2}}$

$\|\vec p\| \approx 14.567\,\frac{kg\cdot m}{s}$

$\theta =\tan^{-1}\left(\frac{-11.661\,\frac{kg\cdot m}{s} }{8.731\,\frac{kg\cdot m}{s} } \right)$

$\theta \approx 306.823^{\circ}$

The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

6 0

3 years ago

3.00 m^3 of water is at 20.0°C.

krok68 [10]

Answer:

9m^3

Explanation:

Given data

volume v1= 3m^3

volume v2= ???

Temperature T1= 20.0°C.

Temperature T2= 60.0°C.

Applying the relation for temperature and volume

V1/T1= V2/T2

substitute

3/20= V2/60

3*60= V2*20

180= 20*V2

180/20= V2

V2= 9m^3

Hence the final volume is 9m^3

6 0

3 years ago

Your first day on the job, you get a call from the owner complaining that her network connection is down. A quick check of the c

mylen [45]

Answer:

TDR means Timeout Detection and Recovery.

Explanation:

TDR is a feature of the Windows operating system which detects response problems from a graphics card, and recovers to a functional desktop by resetting the card. If the operating system does not receive a response from a graphics card within a certain amount of time (default is 2 seconds), the operating system resets the graphics card.

8 0

3 years ago

I need help as fast as possible please ITs DUE IN 10 MINUTES

algol [13]

Answer:

the image is behind the mirror

virtual

erect(not inverted)

larger than the object

3 0

3 years ago

A balloon of diameter 20.0 cm is filled with helium gas at 30°C at 1.00 atm. How

bogdanovich [222]

Answer:

N = 3.54 * 10²³ atoms

Explanation:

The formula to apply here is the idea gas law;

PV = nRT where ;

P= pressure of the gas= 1.013 * 10⁵ Pa

V= volume of the gas = 4/3 * 3.14 *0.15³= 0.01414 m³

n= amount of a substance = ?

R= ideal gas constant= 8.314

T= temperature= 293 K

Applying the values to the formula;

PV = nRT

1.013 * 10⁵ * 0.01414 = n * 8.314*293

n= 1.013 * 10⁵ * 0.01414 / 8.314*293

n= 0.588 moles

1 mole = 6.022 * 10²⁷ atoms/ mole

0.588 moles = 0.588 * 6.022 * 10²⁷

N = 3.54 * 10²³ atoms

8 0

3 years ago