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kakasveta [241]
3 years ago
8

Study the following reaction carefully. What classification should this reaction have? 4Al + 3O 2 2Al 2 O 3 synthesis decomposit

ion single replacement double displacement
Chemistry
1 answer:
allsm [11]3 years ago
8 0

 4 Al  + 3O₂ →  2Al₂O₃

The  classification  of  above reaction is   synthesis

Explanation

  • Synthesis  reaction is type of  chemical reaction in  which two or  more simple  substance combine to form a more complex  product.  React  may be  elements or compounds.
  • In the reaction above Al   combine   with O₂  to form Al₂O₃  therefore it  is synthesis reaction.

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Can someone put in your own words what sensory adaptation is?
Crank

Answer: Sensory adaptation refers to a reduction in sensitivity to a stimulus after constant exposure to it. While sensory adaptation reduces our awareness of a constant stimulus, it helps free up our attention and resources to attend to other stimuli in the environment around us.

Hope this helped!

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4 years ago
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What is meant by the term concentration?
steposvetlana [31]

Answer:

the action or power of focusing one's attention or mental effort.

Explanation:

Keyword: <em>Focus </em>

5 0
4 years ago
What is the sum of protons and neutrons in an atomic nucleus?
Alexxandr [17]
The sum of protons and neutrons in an atomic nucleus would be the MASS NUMBER.
3 0
3 years ago
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Starting with 0.657 g of lead(II) nitrate, a student collects 0.925 g of precipitate. If the calculated mass of precipitate is 0
tatuchka [14]

Answer:

101.2%

Explanation:

Given:

Theoretical yield of the precipitate = 0.914 g

Actual yield of the precipitate = 0.925 g

Now, the percent yield is given as a ratio of actual yield by theoretical yield expressed as a percentage.

Framing in equation form, we have:

\%\ yield=\frac{Actual\ yield}{Theoretical\ yield}\times 100

Now, plug in 0.925 g for actual yield, 0.914 g for theoretical yield and solve for % yield. This gives,

\%\ yield=\frac{0.925\ g}{0.914\ g}\times 100\\\\\%\ yield=1.012\times 100\\\\\%\ yield=101.2\%

Therefore, the percent yield is 101.2%.

5 0
4 years ago
At −15.0 ∘C , a common temperature for household freezers, what is the maximum mass of sucrose (C12H22O11) you can add to 1.50 k
nlexa [21]

Answer: The maximum mass of sucrose you can add is 4158.95 grams.

Explanation:

This is an example of freezing point depression. The formula for calculating this is the following:

ΔT = Kf . b . i

ΔT is the temperature depression

Kf is the cryoscopic constant that is unique for each solvent

b is the molality of the solution (moles of solute per kg of solvent)

i is the Vant Hoff factor

The freezing point of water is 0°C. ΔT equals inicial temperature - final temperature, so it's 0°- (-15°)= 273K - 258K = 15K

The Kf for water is known to be 1.853 K. Kg /mol

i is the number of particles the molecule is split to when ionized. Because sucrose doesn't ionize, its Vant Hoff factor is 1.

If we clear b from the ecuation:

b = ΔT/ Kf . i

b = 15K/ 1.853 K. Kg/mol . 1

b= 8.1 mol/kg

If we can add 8.1 moles to a kg of water before it freezes, we use cross multiplication to calculate how many we can add to 1.5 kg. The answer is 12.15.

The weight of a mole of sucrose is 342.3 grams. So the weight of 12.15 moles of sucrose is 4158.95g.

3 0
3 years ago
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