Question

The gas in a 250. mL piston experiences a change in pressure from 1.00 atm to 4.45 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant

Answer 1

Answer:

56.2 mL

Explanation:

Given data

• Initial volume (V₁): 250 mL

• Initial pressure (P₁): 1.00 atm

• Final volume (V₂): ?

• Final pressure (P₂): 4.45 atm

Assuming the gas has an ideal behavior, we can find the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1.00 atm × 250 mL/ 4.45 atm

V₂ = 56.2 mL