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zysi [14]
3 years ago
11

n order to balance the following reaction S n+Cl 2→ S nCl 4, which coefficient should be inserted in front of chlorine?

Chemistry
1 answer:
victus00 [196]3 years ago
4 0

Answer:

The coefficient that should be inserted in front of chlorine is 2

Explanation:

Sn  +  2Cl₂   →  SnCl₄

As we have 4 atoms of chlorine in product side, we need 4 Cl in reactant side.

Chlorine is a diatomic atom, so if we have 2 mol of it, we are having 4 atoms of Cl.

The law of conservation of mass must be respected in every chemical equation

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Which word names melted rock and minerals found beneath Earth's crust?
Anna11 [10]

before the lava rises to the earth's surface it's called magma. Although lava and magma are often used interchangeably, technically magma is the name for the hot molten rock (mixed with gases and mineral crystals) that collects in chambers beneath the Earth's crust.

Explanation:

8 0
3 years ago
Read 2 more answers
A sample of 0.0860 g of sodium chloride is added to 30.0 mL of 0.050 M silver nitrate, resulting in the formation of a precipita
mestny [16]

Answer:

The answer is:

(a) NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)

(b) NaCl

(c) 0.211 g

Explanation:

Given:

The mass of NaCl,

= 0.0860 g

The molar mass of NaCl,

= 58.44 g/mol

The volume of AgNO_3,

= 30.0 ml

or,

= 0.030 L

Molarity of AgNO_3,

= 0.050 M

Moles of NaCl will be:

= \frac{Given \ mass}{Molar \ mass}

= \frac{0.0860}{58.44}

= 0.00147 \ mol

now,

Moles of AgNO_3 will be:

= Molarity\times Volume

= 0.050\times 0.030

=0.0015 \ mol

(a)

The reaction is:

⇒ NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)

(b)

1 mole of NaCl react with,

= 1 mol of AgNO_3

0.0015 mol AgNO_3 needs,

= 0.00150 \ mol \ NaCl

Available mol of NaCl < needed amount of NaCl

So,

The limiting reagent is "NaCl".

(c)

The precipitate formed,

= 0.00147\times \frac{1}{1}\times \frac{143.32}{1}

= 0.211 \ g \ AgCl

4 0
3 years ago
Explain the changes in potential energy as a chemical bond forms
weqwewe [10]
Energy is released when a chemical bond forms
7 0
3 years ago
HELPP ASAPP
Trava [24]

Answer:

The answer for the calculation is as follows

17.48373

3 0
3 years ago
When this element was discovered, it exhibited luster and malleability, and it reacted very vigorously with water. This element
TEA [102]

Answer:

a) alkali metals

Explanation:

The element described above definitely belonged to the alkali metals, the first group on the periodic table. They show the properties indicated in the text.

  • They are metals because only metals are lustrous and malleable. This eliminates the possibility of them being halogens and noble gases.
  • Only group 1 metals reacts vigorously with water to form alkali.
  • Alkali are aqueous solutions that are basic in nature.
  • The reactivity of group 1 metals is due to their one extra electrons in the outer most shell.
  • These electrons are easily and readily lost in order for such atoms to gain stability and replicate the nearest noble gases.
  • The most reactive metal belongs to this group elements.
  • This is why it is nearly impossible to find them occurring alone in free state.
  • Some of the elements in this group are Li, Na, K, Rb, Cs and Fr.
  • Transition metals have variable oxidation states and some can be found alone in nature.
8 0
2 years ago
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