Question

Ammonia gas can be prepared by the following reaction:CaO(s) + 2NH4Cl(s) ------> 2NH3(g) + H2O(g) + CaCl2(s)In an experiment, 26.5 g of ammonia gas, NH3, is produced when it was predicted that 54.9 g of NH3 would form.What is the theoretical yield of NH3? What is the actual yeild of NH3? What is the percent yeild of NH3?

Answer 1

Answer:

The theoretical yield of NH3 = 54.9 grams

The actual yield of NH3 = 26.5 grams

The % yield = 48.3 %

Explanation:

Step 1: Data given

Mass of NH3 produced = 26.5 grams

54.9 grams of NH3 was predicted

Step 2: The balanced equation:

CaO(s) + 2NH4Cl(s) → 2NH3(g) + H2O(g) + CaCl2(s)

Step 3: Theoretical yield

The theoretical yield, is the amount of NH3 that is predicted to be formed = 54.9 grams

The actual yield is the amount of NH3 that actual has been formed = 26.5 grams

% yield = (actual yield / theoretical yield)*100 %

% yield = (26.5 grams / 54.9 grams) * 100%

% yield = 48.3 %